How to use ffmpeg stream copy within bash "for loop"?

Question

ok i have this and it works but it's slow

for i in *.mov;
  do name=`echo "$i" | cut -d'.' -f1`
  echo "$name"
  ffmpeg -i "$i" "${name}.mp4"
done

I want it to convert with these ffmpeg options

ffmpeg -i movie.mov -vcodec copy -acodec copy out.mp4

score 2 · Answer 1 · answered May 24 '20 at 15:18

2

Parameter expansion is sufficient; you don't need pipelines involving cut.

for i in *.mov; do
    name=${i%%.mov}  # i=foo.mov => name=foo
    ffmpeg -i "$i" "$name.mp4"
done

answered May 24 '20 at 15:18

chepner

Ok thanks! But it stil slow and I read that if "-vcodec copy -acodec" you use it's going to convert much faster. I want to import in premiere – Tom Vanwinkel May 24 '20 at 16:34
You can run instances of of `ffmpeg` in parallel; there is minimal overhead involved in the actual shell. – chepner May 24 '20 at 16:51

Mark Setchell · Answer 2 · 2020-05-24T20:14:34.157

Untested, but you should be able to do them in parallel with GNU Parallel if it's too slow and you have a multicore CPU:

parallel ffmpeg -i {} -vcodec copy -acodec copy {.}.mp4 ::: *.mov

If you want to see what it would do first, without actually doing anything:

parallel --dry-run ffmpeg -i {} -vcodec copy -acodec copy {.}.mp4 ::: *.mov

Note: On macOS, install these two packages simply with homebrew using:

brew install ffmpeg
brew install parallel

score 0 · Answer 3 · answered May 24 '20 at 19:42

0

Use:

for i in *.mov; do ffmpeg -i "$i" -c copy "${i%.*}.mp4"; done

answered May 24 '20 at 19:42

llogan

3 Answers3