Check if URL has content in PHP

Question

I've a PHP file. In this file I need to check, if my URL has the following ending:

www.example.de/dashboard/2/

So the ending can be a number 1 - 99+ which is always at the end of the url between two slashes. I can't use $_GET here. If it is $_GET, it would be easy:

if ( isset($_GET['ending']) ) :

So how can I do this without a parameter in the URL? Thanks for your help!

Lenart12 · Answer 1 · 2019-03-25T21:17:23.393

2

if(preg_match('^\/dashboard\/(\d+)', $_SERVER['REQUEST_URI'])){
    foo();
}

Use regular expression on the request uri

edited Mar 25 '19 at 21:17

answered Mar 25 '19 at 21:08

Lenart12

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I have a problem and try to solve it with RegExp. Now i had two problems :) For this case explode is best way. – Maksim Mar 25 '19 at 21:35
Thanks for spending time and trying to help me! – Mr. Jo Mar 25 '19 at 21:48

Jeto · Accepted Answer · 2019-03-25T21:50:52.007

1

You can make use of parse_url and explode:

$url = 'http://www.example.de/dashboard/2/';

$path = parse_url($url, PHP_URL_PATH); // '/dashboard/2/'
$parts = explode('/', $path);          // ['', 'dashboard', '2', '']
$section = $parts[1];                  // 'dashboard'
$ending = $parts[2];                   // '2'

Demo: https://3v4l.org/dv6Cn

You can also make use of URL rewriting (this is for a Apache-based web server, but you can find simular resources for nginx or any other web servers if need be).

edited Mar 25 '19 at 21:50

answered Mar 25 '19 at 21:06

Jeto

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I'll take this one here because it's simple and it works :) – Mr. Jo Mar 25 '19 at 21:47

score 1 · Answer 3 · answered Mar 25 '19 at 21:10

1

A more dynamic way is to explode and use array_filter to remove empty values then pick the last item.
If the item * 1 is the same as the item then we know it's a number.
(The return from explode is strings so we cant use is_int)

$url = "http://www.example.de/dashboard/2/";
$parts = array_filter(explode("/", $url));
$ending = end($parts);
if($ending*1 == $ending) echo $ending; //2

answered Mar 25 '19 at 21:10

Andreas

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Multiplying a string will yield a warning. – Jeto Mar 25 '19 at 21:22
Now try with an URL that doesn't end with a "number". PHP somehow manages to do it with strings such as "2" because it's an awful language, but still :) – Jeto Mar 25 '19 at 21:40
Thanks for spending time and trying to help me! – Mr. Jo Mar 25 '19 at 21:47

Maksim · Answer 4 · 2019-03-25T22:02:30.207

1

First you need to target this url to script - in web server config. For nginx and index.php:

try_files $uri @rewrite_location;
location @rewrite_location {
        rewrite ^/(.*) /index.php?link=$1&$args last;
}

Second - you need to parse URI. In $end you find what you want

$link_as_array = array_values(array_diff(explode("/", $url), array('')));
$max = count($link_as_array) - 1;
$end = $link_as_array[$max];

edited Mar 25 '19 at 22:02

answered Mar 25 '19 at 21:21

Maksim

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No problem, but you know you can try your code before posting? https://3v4l.org/uEnLp – Andreas Mar 25 '19 at 21:46
Thanks for spending time and trying to help me! – Mr. Jo Mar 25 '19 at 21:48
Oh, need to go asleep, forget about last slash. But this code is not fine at all, this is mock, not production ready. – Maksim Mar 25 '19 at 22:02

Praveen Kumar Purushothaman · Answer 5 · 2019-03-25T21:02:55.600

0

I would think this way. If the URL is always the same, or the same format, I'll do the following:

Check for the approx URL.
Split the URL into pieces.
Find if there's the part I am looking for.
Extract the number.

<?php
  $url = "http://www.example.de/dashboard/2/";
  if (strpos($url, "www.example.de/dashboard") === 7 or strpos($url, "www.example.de/dashboard") === 8) {
    $urlParts = explode("/", $url);
    if (isset($urlParts[4]) && isNumeric($urlParts[4]))
      echo "Yes! It is {$urlParts[4]}.";
  }
?>

The strpos with 7 and 8 is for URL with http:// or https://.

The above will give you the output as the numeric part if it is set. I hope this works out.

edited Mar 25 '19 at 21:02

answered Mar 25 '19 at 21:01

Praveen Kumar Purushothaman

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I think your `explode` is missing an argument :) – Jeto Mar 25 '19 at 21:02
1

@Jeto Thanks a lot. I have corrected the errors. There were two. ‍♂️ – Praveen Kumar Purushothaman Mar 25 '19 at 21:03
Why not doing $urlParts[-1] ? – TintinSansYeux Mar 25 '19 at 21:04
@MsuArven Not valid in PHP (unless you explicitly have a `-1` index in your array). – Jeto Mar 25 '19 at 21:08
@MsuArven Reason being if you have a URL with more params, say `dashboard/2/hello/world`, your option will not work. I am trying to get the next directory after `dashboard`. – Praveen Kumar Purushothaman Mar 25 '19 at 21:11
@Jeto Uh ? I'm doing it, it's 100% valid. – TintinSansYeux Mar 25 '19 at 21:11
@MsuArven & Praveen [No it doesn't?](https://3v4l.org/iI7jc) It only works with strings. – Jeto Mar 25 '19 at 21:15
`dashboard/2/hello/world` is not what OP request in question. It's the ending that needs to be captured – Andreas Mar 25 '19 at 21:15
@MsuArven Yep, it doesn't work. https://eval.in/1087330 & https://eval.in/1087329 – Praveen Kumar Purushothaman Mar 25 '19 at 21:16
@Andreas Another way of thinking in the future, what if the URL gets new stuff added? – Praveen Kumar Purushothaman Mar 25 '19 at 21:17
In that case, another way of thinking. What if a new folder is created above? – Andreas Mar 25 '19 at 21:18
1

@Andreas No comments. – Praveen Kumar Purushothaman Mar 25 '19 at 21:19
1

Thanks for spending time and trying to help me! – Mr. Jo Mar 25 '19 at 21:47

Check if URL has content in PHP

5 Answers5