Consider two computers A and B. A has uses G and B uses G' where G' != G and of different degrees. Computer A wants to send a data D and it uses CRC for that cause.
The claim says that there couldn't be a scenario where A sends a CRC-message corresponding to data D and computer B will accept it as a valid message. Why is that?
We know that computer A sends D*2^r XOR R (r is the degree of G) and computer B divides by G'. So in other words, why can't G', accidentally, divide D*2^r XOR R?
Obviously it has something to do with the fact that deg(G) != deg(G') but I didn't figure it out.
Thanks!
