How to recursively find the latest modified file in a directory?

Question

It seems that ls doesn't sort the files correctly when doing a recursive call:

ls -altR . | head -n 3

How can I find the most recently modified file in a directory (including subdirectories)?

Answer 1

find . -type f -printf '%T@ %p\n' \
| sort -n | tail -1 | cut -f2- -d" "

For a huge tree, it might be hard for sort to keep everything in memory.

%T@ gives you the modification time like a unix timestamp, sort -n sorts numerically, tail -1 takes the last line (highest timestamp), cut -f2 -d" " cuts away the first field (the timestamp) from the output.

Edit: Just as -printf is probably GNU-only, ajreals usage of stat -c is too. Although it is possible to do the same on BSD, the options for formatting is different (-f "%m %N" it would seem)

And I missed the part of plural; if you want more then the latest file, just bump up the tail argument.

Answer 2

Following up on @plundra's answer, here's the BSD and OS X version:

find . -type f -print0 \
| xargs -0 stat -f "%m %N" \
| sort -rn | head -1 | cut -f2- -d" "

Answer 3

Instead of sorting the results and keeping only the last modified ones, you could use awk to print only the one with greatest modification time (in unix time):

find . -type f -printf "%T@\0%p\0" | awk '
    {
        if ($0>max) {
            max=$0; 
            getline mostrecent
        } else 
            getline
    } 
    END{print mostrecent}' RS='\0'

This should be a faster way to solve your problem if the number of files is big enough.

I have used the NUL character (i.e. '\0') because, theoretically, a filename may contain any character (including space and newline) but that.

If you don't have such pathological filenames in your system you can use the newline character as well:

find . -type f -printf "%T@\n%p\n" | awk '
    {
        if ($0>max) {
            max=$0; 
            getline mostrecent
        } else 
            getline
    } 
    END{print mostrecent}' RS='\n'

In addition, this works in mawk too.

Answer 4

This seems to work fine, even with subdirectories:

find . -type f | xargs ls -ltr | tail -n 1

In case of too many files, refine the find.

Answer 5

I had the trouble to find the last modified file under Solaris 10. There find does not have the printf option and stat is not available. I discovered the following solution which works well for me:

find . -type f | sed 's/.*/"&"/' | xargs ls -E | awk '{ print $6," ",$7 }' | sort | tail -1

To show the filename as well use

find . -type f | sed 's/.*/"&"/' | xargs ls -E | awk '{ print $6," ",$7," ",$9 }' | sort | tail -1

Explanation

• find . -type f finds and lists all files
• sed 's/.*/"&"/' wraps the pathname in quotes to handle whitespaces
• xargs ls -E sends the quoted path to ls, the -E option makes sure that a full timestamp (format year-month-day hour-minute-seconds-nanoseconds) is returned
• awk '{ print $6," ",$7 }' extracts only date and time
• awk '{ print $6," ",$7," ",$9 }' extracts date, time and filename
• sort returns the files sorted by date
• tail -1 returns only the last modified file

Answer 6

Shows the latest file with human readable timestamp:

find . -type f -printf '%TY-%Tm-%Td %TH:%TM: %Tz %p\n'| sort -n | tail -n1

Result looks like this:

2015-10-06 11:30: +0200 ./foo/bar.txt

To show more files, replace -n1 with a higher number

Answer 7

I use something similar all the time, as well as the top-k list of most recently modified files. For large directory trees, it can be much faster to avoid sorting. In the case of just top-1 most recently modified file:

find . -type f -printf '%T@ %p\n' | perl -ne '@a=split(/\s+/, $_, 2); ($t,$f)=@a if $a[0]>$t; print $f if eof()'

On a directory containing 1.7 million files, I get the most recent one in 3.4s, a speed-up of 7.5x against the 25.5s solution using sort.

Answer 8

This gives a sorted list:

find . -type f -ls 2>/dev/null | sort -M -k8,10 | head -n5

Reverse the order by placing a '-r' in the sort command. If you only want filenames, insert "awk '{print $11}' |" before '| head'

Answer 9

On Ubuntu 13, the following does it, maybe a tad faster, as it reverses the sort and uses 'head' instead of 'tail', reducing the work. To show the 11 newest files in a tree:

find . -type f -printf '%T@ %p\n' | sort -n -r | head -11 | cut -f2- -d" " | sed -e 's,^./,,' | xargs ls -U -l

This gives a complete ls listing without re-sorting and omits the annoying './' that 'find' puts on every file name.

Or, as a bash function:

treecent () {
  local numl
  if [[ 0 -eq $# ]] ; then
    numl=11   # Or whatever default you want.
  else
    numl=$1
  fi
  find . -type f -printf '%T@ %p\n' | sort -n -r | head -${numl} |  cut -f2- -d" " | sed -e 's,^\./,,' | xargs ls -U -l
}

Still, most of the work was done by plundra's original solution. Thanks plundra.

Answer 10

I faced the same issue. I need to find the most recent file recursively. find took around 50 minutes to find.

Here is a little script to do it faster:

#!/bin/sh

CURRENT_DIR='.'

zob () {
    FILE=$(ls -Art1 ${CURRENT_DIR} | tail -n 1)
    if [ ! -f ${FILE} ]; then
        CURRENT_DIR="${CURRENT_DIR}/${FILE}"
        zob
    fi
    echo $FILE
    exit
}
zob

It's a recursive function who get the most recent modified item of a directory. If this item is a directory, the function is called recursively and search into this directory, etc.

Answer 11

I find the following shorter and with more interpretable output:

find . -type f -printf '%TF %TT %p\n' | sort | tail -1

Given the fixed length of the standardised ISO format datetimes, lexicographical sorting is fine and we don't need the -n option on the sort.

If you want to remove the timestamps again, you can use:

find . -type f -printf '%TFT%TT %p\n' | sort | tail -1 | cut -f2- -d' '

Answer 12

If running stat on each file individually is to slow you can use xargs to speed things up a bit:

find . -type f -print0 | xargs -0 stat -f "%m %N" | sort -n | tail -1 | cut -f2- -d" " 

Answer 13

This recursively changes the modification time of all directories in the current directory to the newest file in each directory:

for dir in */; do find $dir -type f -printf '%T@ "%p"\n' | sort -n | tail -1 | cut -f2- -d" " | xargs -I {} touch -r {} $dir; done

Answer 14

This simple cli will also work:

ls -1t | head -1

You may change the -1 to the number of files you want to list

Answer 15

I found the command above useful, but for my case I needed to see the date and time of the file as well I had an issue with several files that have spaces in the names. Here is my working solution.

find . -type f -printf '%T@ %p\n' | sort -n | tail -1 | cut -f2- -d" " | sed 's/.*/"&"/' | xargs ls -l

Answer 16

I prefer this one, it is shorter:

find . -type f -print0|xargs -0 ls -drt|tail -n 1

Answer 17

The following command worked on Solaris :

find . -name "*zip" -type f | xargs ls -ltr | tail -1 

Answer 18

I wrote a pypi/github package for this question because I needed a solution as well.

https://github.com/bucknerns/logtail

Install:

pip install logtail

Usage: tails changed files

logtail <log dir> [<glob match: default=*.log>]

Usage2: Opens latest changed file in editor

editlatest <log dir> [<glob match: default=*.log>]

Answer 19

Ignoring hidden files — with nice & fast time stamp

Here is how to find and list the latest modified files in a directory with subdirectories. Hidden files are ignored on purpose. The time format can be customised.

$ find . -type f -not -path '*/\.*' -printf '%TY.%Tm.%Td %THh%TM %Ta %p\n' |sort -nr |head -n 10

Result

Handles spaces in filenames well — not that these should be used!

2017.01.25 18h23 Wed ./indenting/Shifting blocks visually.mht
2016.12.11 12h33 Sun ./tabs/Converting tabs to spaces.mht
2016.12.02 01h46 Fri ./advocacy/2016.Vim or Emacs - Which text editor do you prefer?.mht
2016.11.09 17h05 Wed ./Word count - Vim Tips Wiki.mht

More

More find galore following the link.

Answer 20

To search for files in /target_directory and all its sub-directories, that have been modified in the last 60 minutes:

$ find /target_directory -type f -mmin -60

To find the most recently modified files, sorted in the reverse order of update time (i.e., the most recently updated files first):

$ find /etc -type f -printf '%TY-%Tm-%Td %TT %p\n' | sort -r

Answer 21

After using a find-based solution for years, I found myself wanting the ability to exclude directories like .git.

I switched to this rsync-based solution. Put this in ~/bin/findlatest:

#!/bin/sh
# Finds most recently modified files.
rsync -rL --list-only "$@" | grep -v '^d' | sort -k3,4r | head -5

Now findlatest . will list the 5 most recently modified files, and findlatest --exclude .git . will list the 5 excluding ones in .git.

This works by taking advantage of some little-used rsync functionality: "if a single source arg is specified [to rsync] without a destination, the files are listed in an output format similar to ls -l" (rsync man page).

The ability to take rsync args is useful in conjunction with rsync-based backup tools. For instance I use rsnapshot, and I back up an application directory with rsnapshot.conf line:

backup  /var/atlassian/application-data/jira/current/   home    +rsync_long_args=--archive --filter="merge /opt/atlassian/jira/current/backups/rsync-excludes"

where rsync-excludes lists directories I don't want to backup:

- log/
- logs/
- analytics-logs/
- tmp/
- monitor/*.rrd4j

I can see now the latest files that will be backed up with:

findlatest /var/atlassian/application-data/jira/current/ --filter="merge /opt/atlassian/jira/current/backups/rsync-excludes"