C++ name mangling decoder for g++?

Question

is there any C++ name-mangling decoder for g++?

Voting to reopen: http://stackoverflow.com/questions/4465872/why-does-typeid-name-return-weird-characters-using-gcc-and-how-to-make-it-prin clearly requires it to be from inside the code, and only for types, which never appear on object files (as opposed to functions). This one is usually interpreted as "on object files from the command line". — Ciro Santilli新疆棉花TRUMP BAN BAD, Jun 05 '15 at 13:28
it old but I have been helped by this site a lot https://demangler.com/ — Stefano Mtangoo, Mar 06 '16 at 11:08

score 57 · Accepted Answer · answered Dec 17 '10 at 08:31

57

You can use c++filt to demangle c++ symbols. For instance

$ c++filt -n _Z1fv
f()

answered Dec 17 '10 at 08:31

ryan_s

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score 12 · Answer 2 · edited May 23 '17 at 12:18

12

c++filt, example usage here:

Can we see the template instantiated code by C++ compiler

edited May 23 '17 at 12:18

Community

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answered Dec 17 '10 at 08:30

qdot

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score 2 · Answer 3 · edited May 23 '17 at 12:02

You may also be interested on the -C option of objdump:

objdump -CSr main.o

which demangles relocation references like:

  char *sn = new char[4];
10:   bf 04 00 00 00          mov    $0x4,%edi
15:   e8 00 00 00 00          callq  1a <main+0x1a>
                      16: R_X86_64_PC32       operator new[](unsigned long)-0x4

Without -C it would show the mangled name _Znam.

See also: Can objdump un-mangle names of C++ template functions?

There are also some online demanglers mentioned at Is there an online name demangler for C++? like http://demangler.com/ If it exists, there is SaaS of it.

nm also has a -C option.

or even `objdump -CSr main.o | less --pattern=_Znam` – Paweł Prażak Feb 26 '16 at 17:06 — Paweł Prażak, Feb 26 '16 at 17:06

C++ name mangling decoder for g++?

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