PHP Explode Array returns text 'Array'

Question

I'm using a breadcrumb script for it's obvious use, and I am trying to remove &anyqueryafterhere from the result. I'm using for each to go through the array to remove this, but it returns 'Array'. The code I have is

if(empty($breadcrumbs)===false){
    foreach($breadcrumbs as &$r){
        $r = explode("&", $r);  
    }
}

Currently, it, as mentioned before, just returns Array, so it shows as something like Array » Array. So first question, what's the cause of this, and second, how can I sort it? Thanks in advance.

You realize that is only going to return the last $breadcrumbs right? You're overwriting $r with each iteration of the foreach loop. (that is after you remove that & from the foreach of course) — Rick Calder, Dec 09 '12 at 14:55
How exactly is he modifying anything in the above code? Other than overwriting $r of course. — Rick Calder, Dec 09 '12 at 14:58
He is overwriting `$r` by reference. In PHP, his line: `$r = explode("&", $r)` is the same as `$breadcrumbs[$key] = explode("&", $r)`. He is modifying the source array because it is being passed *by reference* — Colin M, Dec 09 '12 at 15:02

score 2 · Answer 1 · edited May 23 '17 at 10:24

2

try

foreach($breadcrumbs as &$r){
                        ^-----is reference operator ..remove this Those are references, they are similar to "pointers" in C or C++. 

foreach($breadcrumbs as $r){

and

if(empty($breadcrumbs)===false){

better approach will be

 if(!empty($breadcrumbs)){...}

Good Read

How does “&” operator work in PHP function?

edited May 23 '17 at 10:24

Community

1
1

answered Dec 09 '12 at 15:02

NullPoiиteя

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score 1 · Accepted Answer · answered Dec 09 '12 at 14:54

1

Replace

foreach($breadcrumbs as &$r){

With:

foreach($breadcrumbs as $r){

Remove the &.

answered Dec 09 '12 at 14:54

Praveen Kumar Purushothaman

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Works perfectly now! Thank you very much! – ChocCookieRaider Dec 09 '12 at 14:56

PHP Explode Array returns text 'Array'

2 Answers2

Replace

With: