How can I create a memory leak in Java?

Question

I just had an interview, and I was asked to create a memory leak with Java.

Needless to say, I felt pretty dumb having no clue on how to even start creating one.

What would an example be?

Answer 1

Here's a good way to create a true memory leak (objects inaccessible by running code but still stored in memory) in pure Java:

1. The application creates a long-running thread (or use a thread pool to leak even faster).
2. The thread loads a class via an (optionally custom) ClassLoader.
3. The class allocates a large chunk of memory (e.g. new byte[1000000]), stores a strong reference to it in a static field, and then stores a reference to itself in a ThreadLocal. Allocating the extra memory is optional (leaking the class instance is enough), but it will make the leak work that much faster.
4. The application clears all references to the custom class or the ClassLoader it was loaded from.
5. Repeat.

Due to the way ThreadLocal is implemented in Oracle's JDK, this creates a memory leak:

• Each Thread has a private field threadLocals, which actually stores the thread-local values.
• Each key in this map is a weak reference to a ThreadLocal object, so after that ThreadLocal object is garbage-collected, its entry is removed from the map.
• But each value is a strong reference, so when a value (directly or indirectly) points to the ThreadLocal object that is its key, that object will neither be garbage-collected nor removed from the map as long as the thread lives.

In this example, the chain of strong references looks like this:

Thread object → threadLocals map → instance of example class → example class → static ThreadLocal field → ThreadLocal object.

(The ClassLoader doesn't really play a role in creating the leak, it just makes the leak worse because of this additional reference chain: example class → ClassLoader → all the classes it has loaded. It was even worse in many JVM implementations, especially prior to Java 7, because classes and ClassLoaders were allocated straight into permgen and were never garbage-collected at all.)

A variation on this pattern is why application containers (like Tomcat) can leak memory like a sieve if you frequently redeploy applications which happen to use ThreadLocals that in some way point back to themselves. This can happen for a number of subtle reasons and is often hard to debug and/or fix.

Update: Since lots of people keep asking for it, here's some example code that shows this behavior in action.

Answer 2

Static field holding an object reference [especially a final field]

class MemorableClass {
    static final ArrayList list = new ArrayList(100);
}

Calling String.intern() on a lengthy string

String str = readString(); // read lengthy string any source db,textbox/jsp etc..
// This will place the string in memory pool from which you can't remove
str.intern();

(Unclosed) open streams (file , network, etc.)

try {
    BufferedReader br = new BufferedReader(new FileReader(inputFile));
    ...
    ...
} catch (Exception e) {
    e.printStacktrace();
}

Unclosed connections

try {
    Connection conn = ConnectionFactory.getConnection();
    ...
    ...
} catch (Exception e) {
    e.printStacktrace();
}

Areas that are unreachable from JVM's garbage collector, such as memory allocated through native methods.

In web applications, some objects are stored in application scope until the application is explicitly stopped or removed.

getServletContext().setAttribute("SOME_MAP", map);

Incorrect or inappropriate JVM options, such as the noclassgc option on IBM JDK that prevents unused class garbage collection

See IBM JDK settings.

Answer 3

A simple thing to do is to use a HashSet with an incorrect (or non-existent) hashCode() or equals(), and then keep adding "duplicates". Instead of ignoring duplicates as it should, the set will only ever grow and you won't be able to remove them.

If you want these bad keys/elements to hang around you can use a static field like

class BadKey {
   // no hashCode or equals();
   public final String key;
   public BadKey(String key) { this.key = key; }
}

Map map = System.getProperties();
map.put(new BadKey("key"), "value"); // Memory leak even if your threads die.

Answer 4

Below there will be a non-obvious case where Java leaks, besides the standard case of forgotten listeners, static references, bogus/modifiable keys in hashmaps, or just threads stuck without any chance to end their life-cycle.

• File.deleteOnExit() - always leaks the string, if the string is a substring, the leak is even worse (the underlying char[] is also leaked) - in Java 7 substring also copies the char[], so the later doesn't apply; @Daniel, no needs for votes, though.

I'll concentrate on threads to show the danger of unmanaged threads mostly, don't wish to even touch swing.

• Runtime.addShutdownHook and not remove... and then even with removeShutdownHook due to a bug in ThreadGroup class regarding unstarted threads it may not get collected, effectively leak the ThreadGroup. JGroup has the leak in GossipRouter.

• Creating, but not starting, a Thread goes into the same category as above.

• Creating a thread inherits the ContextClassLoader and AccessControlContext, plus the ThreadGroup and any InheritedThreadLocal, all those references are potential leaks, along with the entire classes loaded by the classloader and all static references, and ja-ja. The effect is especially visible with the entire j.u.c.Executor framework that features a super simple ThreadFactory interface, yet most developers have no clue of the lurking danger. Also a lot of libraries do start threads upon request (way too many industry popular libraries).

• ThreadLocal caches; those are evil in many cases. I am sure everyone has seen quite a bit of simple caches based on ThreadLocal, well the bad news: if the thread keeps going more than expected the life the context ClassLoader, it is a pure nice little leak. Do not use ThreadLocal caches unless really needed.

• Calling ThreadGroup.destroy() when the ThreadGroup has no threads itself, but it still keeps child ThreadGroups. A bad leak that will prevent the ThreadGroup to remove from its parent, but all the children become un-enumerateable.

• Using WeakHashMap and the value (in)directly references the key. This is a hard one to find without a heap dump. That applies to all extended Weak/SoftReference that might keep a hard reference back to the guarded object.

• Using java.net.URL with the HTTP(S) protocol and loading the resource from(!). This one is special, the KeepAliveCache creates a new thread in the system ThreadGroup which leaks the current thread's context classloader. The thread is created upon the first request when no alive thread exists, so either you may get lucky or just leak. The leak is already fixed in Java 7 and the code that creates thread properly removes the context classloader. There are few more cases (like ImageFetcher, also fixed) of creating similar threads.

• Using InflaterInputStream passing new java.util.zip.Inflater() in the constructor (PNGImageDecoder for instance) and not calling end() of the inflater. Well, if you pass in the constructor with just new, no chance... And yes, calling close() on the stream does not close the inflater if it's manually passed as constructor parameter. This is not a true leak since it'd be released by the finalizer... when it deems it necessary. Till that moment it eats native memory so badly it can cause Linux oom_killer to kill the process with impunity. The main issue is that finalization in Java is very unreliable and G1 made it worse till 7.0.2. Moral of the story: release native resources as soon as you can; the finalizer is just too poor.

• The same case with java.util.zip.Deflater. This one is far worse since Deflater is memory hungry in Java, i.e. always uses 15 bits (max) and 8 memory levels (9 is max) allocating several hundreds KB of native memory. Fortunately, Deflater is not widely used and to my knowledge JDK contains no misuses. Always call end() if you manually create a Deflater or Inflater. The best part of the last two: you can't find them via normal profiling tools available.

(I can add some more time wasters I have encountered upon request.)

Good luck and stay safe; leaks are evil!

Answer 5

Most examples here are "too complex". They are edge cases. With these examples, the programmer made a mistake (like don't redefining equals/hashcode), or has been bitten by a corner case of the JVM/JAVA (load of class with static...). I think that's not the type of example an interviewer want or even the most common case.

But there are really simpler cases for memory leaks. The garbage collector only frees what is no longer referenced. We as Java developers don't care about memory. We allocate it when needed and let it be freed automatically. Fine.

But any long-lived application tend to have shared state. It can be anything, statics, singletons... Often non-trivial applications tend to make complex objects graphs. Just forgetting to set a reference to null or more often forgetting to remove one object from a collection is enough to make a memory leak.

Of course all sort of listeners (like UI listeners), caches, or any long-lived shared state tend to produce memory leak if not properly handled. What shall be understood is that this is not a Java corner case, or a problem with the garbage collector. It is a design problem. We design that we add a listener to a long-lived object, but we don't remove the listener when no longer needed. We cache objects, but we have no strategy to remove them from the cache.

We maybe have a complex graph that store the previous state that is needed by a computation. But the previous state is itself linked to the state before and so on.

Like we have to close SQL connections or files. We need to set proper references to null and remove elements from the collection. We shall have proper caching strategies (maximum memory size, number of elements, or timers). All objects that allow a listener to be notified must provide both a addListener and removeListener method. And when these notifiers are no longer used, they must clear their listener list.

A memory leak is indeed truly possible and is perfectly predictable. No need for special language features or corner cases. Memory leaks are either an indicator that something is maybe missing or even of design problems.

Answer 6

The answer depends entirely on what the interviewer thought they were asking.

Is it possible in practice to make Java leak? Of course it is, and there are plenty of examples in the other answers.

But there are multiple meta-questions that may have been being asked?

• Is a theoretically "perfect" Java implementation vulnerable to leaks?
• Does the candidate understand the difference between theory and reality?
• Does the candidate understand how garbage collection works?
• Or how garbage collection is supposed to work in an ideal case?
• Do they know they can call other languages through native interfaces?
• Do they know to leak memory in those other languages?
• Does the candidate even know what memory management is, and what is going on behind the scene in Java?

I'm reading your meta-question as "What's an answer I could have used in this interview situation". And hence, I'm going to focus on interview skills instead of Java. I believe you're more likely to repeat the situation of not knowing the answer to a question in an interview than you are to be in a place of needing to know how to make Java leak. So, hopefully, this will help.

One of the most important skills you can develop for interviewing is learning to actively listen to the questions and working with the interviewer to extract their intent. Not only does this let you answer their question the way they want, but also shows that you have some vital communication skills. And when it comes down to a choice between many equally talented developers, I'll hire the one who listens, thinks, and understands before they respond every time.

Answer 7

The following is a pretty pointless example, if you do not understand JDBC. Or at least how JDBC expects a developer to close Connection, Statement and ResultSet instances before discarding them or losing references to them, instead of relying on the implementation of finalize.

void doWork()
{
   try
   {
       Connection conn = ConnectionFactory.getConnection();
       PreparedStatement stmt = conn.preparedStatement("some query"); // executes a valid query
       ResultSet rs = stmt.executeQuery();
       while(rs.hasNext())
       {
          ... process the result set
       }
   }
   catch(SQLException sqlEx)
   {
       log(sqlEx);
   }
}

The problem with the above is that the Connection object is not closed, and hence the physical connection will remain open, until the garbage collector comes around and sees that it is unreachable. GC will invoke the finalize method, but there are JDBC drivers that do not implement the finalize, at least not in the same way that Connection.close is implemented. The resulting behavior is that while memory will be reclaimed due to unreachable objects being collected, resources (including memory) associated with the Connection object might simply not be reclaimed.

In such an event where the Connection's finalize method does not clean up everything, one might actually find that the physical connection to the database server will last several garbage collection cycles, until the database server eventually figures out that the connection is not alive (if it does), and should be closed.

Even if the JDBC driver were to implement finalize, it is possible for exceptions to be thrown during finalization. The resulting behavior is that any memory associated with the now "dormant" object will not be reclaimed, as finalize is guaranteed to be invoked only once.

The above scenario of encountering exceptions during object finalization is related to another other scenario that could possibly lead to a memory leak - object resurrection. Object resurrection is often done intentionally by creating a strong reference to the object from being finalized, from another object. When object resurrection is misused it will lead to a memory leak in combination with other sources of memory leaks.

There are plenty more examples that you can conjure up - like

• Managing a List instance where you are only adding to the list and not deleting from it (although you should be getting rid of elements you no longer need), or
• Opening Sockets or Files, but not closing them when they are no longer needed (similar to the above example involving the Connection class).
• Not unloading Singletons when bringing down a Java EE application. Apparently, the Classloader that loaded the singleton class will retain a reference to the class, and hence the singleton instance will never be collected. When a new instance of the application is deployed, a new class loader is usually created, and the former class loader will continue to exist due to the singleton.

Answer 8

Probably one of the simplest examples of a potential memory leak, and how to avoid it, is the implementation of ArrayList.remove(int):

public E remove(int index) {
    RangeCheck(index);

    modCount++;
    E oldValue = (E) elementData[index];

    int numMoved = size - index - 1;
    if (numMoved > 0)
        System.arraycopy(elementData, index + 1, elementData, index,
                numMoved);
    elementData[--size] = null; // (!) Let gc do its work

    return oldValue;
}

If you were implementing it yourself, would you have thought to clear the array element that is no longer used (elementData[--size] = null)? That reference might keep a huge object alive ...

Answer 9

Any time you keep references around to objects that you no longer need you have a memory leak. See Handling memory leaks in Java programs for examples of how memory leaks manifest themselves in Java and what you can do about it.

Answer 10

You are able to make memory leak with sun.misc.Unsafe class. In fact this service class is used in different standard classes (for example in java.nio classes). You can't create instance of this class directly, but you may use reflection to do that.

Code doesn't compile in the Eclipse IDE - compile it using command javac (during compilation you'll get warnings)

import java.lang.reflect.Constructor;
import java.lang.reflect.Field;
import sun.misc.Unsafe;


public class TestUnsafe {

    public static void main(String[] args) throws Exception{
        Class unsafeClass = Class.forName("sun.misc.Unsafe");
        Field f = unsafeClass.getDeclaredField("theUnsafe");
        f.setAccessible(true);
        Unsafe unsafe = (Unsafe) f.get(null);
        System.out.print("4..3..2..1...");
        try
        {
            for(;;)
                unsafe.allocateMemory(1024*1024);
        } catch(Error e) {
            System.out.println("Boom :)");
            e.printStackTrace();
        }
    }
}

Answer 11

I can copy my answer from here: Easiest way to cause memory leak in Java

"A memory leak, in computer science (or leakage, in this context), occurs when a computer program consumes memory but is unable to release it back to the operating system." (Wikipedia)

The easy answer is: You can't. Java does automatic memory management and will free resources that are not needed for you. You can't stop this from happening. It will always be able to release the resources. In programs with manual memory management, this is different. You can get some memory in C using malloc(). To free the memory, you need the pointer that malloc returned and call free() on it. But if you don't have the pointer any more (overwritten, or lifetime exceeded), then you are unfortunately incapable of freeing this memory and thus you have a memory leak.

All the other answers so far are in my definition not really memory leaks. They all aim at filling the memory with pointless stuff real fast. But at any time you could still dereference the objects you created and thus freeing the memory --> no leak. acconrad's answer comes pretty close though as I have to admit since his solution is effectively to just "crash" the garbage collector by forcing it in an endless loop).

The long answer is: You can get a memory leak by writing a library for Java using the JNI, which can have manual memory management and thus have memory leaks. If you call this library, your Java process will leak memory. Or, you can have bugs in the JVM, so that the JVM looses memory. There are probably bugs in the JVM, there may even be some known ones since garbage collection is not that trivial, but then it's still a bug. By design this is not possible. You may be asking for some Java code that is effected by such a bug. Sorry I don't know one and it might well not be a bug any more in the next Java version anyway.

Answer 12

Here's a simple/sinister one via http://wiki.eclipse.org/Performance_Bloopers#String.substring.28.29.

public class StringLeaker
{
    private final String muchSmallerString;

    public StringLeaker()
    {
        // Imagine the whole Declaration of Independence here
        String veryLongString = "We hold these truths to be self-evident...";

        // The substring here maintains a reference to the internal char[]
        // representation of the original string.
        this.muchSmallerString = veryLongString.substring(0, 1);
    }
}

Because the substring refers to the internal representation of the original, much longer string, the original stays in memory. Thus, as long as you have a StringLeaker in play, you have the whole original string in memory, too, even though you might think you're just holding on to a single-character string.

The way to avoid storing an unwanted reference to the original string is to do something like this:

...
this.muchSmallerString = new String(veryLongString.substring(0, 1));
...

For added badness, you might also .intern() the substring:

...
this.muchSmallerString = veryLongString.substring(0, 1).intern();
...

Doing so will keep both the original long string and the derived substring in memory even after the StringLeaker instance has been discarded.

Answer 13

A common example of this in GUI code is when creating a widget/component and adding a listener to some static/application scoped object and then not removing the listener when the widget is destroyed. Not only do you get a memory leak, but also a performance hit as when whatever you are listening to fires events, all your old listeners are called too.

Answer 14

Maybe by using external native code through JNI?

With pure Java, it is almost impossible.

But that is about a "standard" type of memory leak, when you cannot access the memory anymore, but it is still owned by the application. You can instead keep references to unused objects, or open streams without closing them afterwards.

Answer 15

Take any web application running in any servlet container (Tomcat, Jetty, GlassFish, whatever...). Redeploy the application 10 or 20 times in a row (it may be enough to simply touch the WAR in the server's autodeploy directory.

Unless anybody has actually tested this, chances are high that you'll get an OutOfMemoryError after a couple of redeployments, because the application did not take care to clean up after itself. You may even find a bug in your server with this test.

The problem is, the lifetime of the container is longer than the lifetime of your application. You have to make sure that all references the container might have to objects or classes of your application can be garbage collected.

If there is just one reference surviving the undeployment of your web application, the corresponding classloader and by consequence all classes of your web application cannot be garbage collected.

Threads started by your application, ThreadLocal variables, logging appenders are some of the usual suspects to cause classloader leaks.

Answer 16

I have had a nice "memory leak" in relation to PermGen and XML parsing once. The XML parser we used (I can't remember which one it was) did a String.intern() on tag names, to make comparison faster. One of our customers had the great idea to store data values not in XML attributes or text, but as tagnames, so we had a document like:

<data>
   <1>bla</1>
   <2>foo</>
   ...
</data>

In fact, they did not use numbers but longer textual IDs (around 20 characters), which were unique and came in at a rate of 10-15 million a day. That makes 200 MB of rubbish a day, which is never needed again, and never GCed (since it is in PermGen). We had permgen set to 512 MB, so it took around two days for the out-of-memory exception (OOME) to arrive...

Answer 17

What's a memory leak:

• It's caused by a bug or bad design.
• It's a waste of memory.
• It gets worse over time.
• The garbage collector cannot clean it.

Typical example:

A cache of objects is a good starting point to mess things up.

private static final Map<String, Info> myCache = new HashMap<>();

public void getInfo(String key)
{
    // uses cache
    Info info = myCache.get(key);
    if (info != null) return info;

    // if it's not in cache, then fetch it from the database
    info = Database.fetch(key);
    if (info == null) return null;

    // and store it in the cache
    myCache.put(key, info);
    return info;
}

Your cache grows and grows. And pretty soon the entire database gets sucked into memory. A better design uses an LRUMap (Only keeps recently used objects in cache).

Sure, you can make things a lot more complicated:

• using ThreadLocal constructions.
• adding more complex reference trees.
• or leaks caused by 3rd party libraries.

What often happens:

If this Info object has references to other objects, which again have references to other objects. In a way you could also consider this to be some kind of memory leak, (caused by bad design).

Answer 18

The interviewer was probably looking for a circular reference like the code below (which incidentally only leak memory in very old JVMs that used reference counting, which isn't the case any more). But it's a pretty vague question, so it's a prime opportunity to show off your understanding of JVM memory management.

class A {
    B bRef;
}

class B {
    A aRef;
}

public class Main {
    public static void main(String args[]) {
        A myA = new A();
        B myB = new B();
        myA.bRef = myB;
        myB.aRef = myA;
        myA=null;
        myB=null;
        /* at this point, there is no access to the myA and myB objects, */
        /* even though both objects still have active references. */
    } /* main */
}

Then you can explain that with reference counting, the above code would leak memory. But most modern JVMs don't use reference counting any longer. Most use a sweep garbage collector, which will in fact collect this memory.

Next you might explain creating an Object that has an underlying native resource, like this:

public class Main {
    public static void main(String args[]) {
        Socket s = new Socket(InetAddress.getByName("google.com"),80);
        s=null;
        /* at this point, because you didn't close the socket properly, */
        /* you have a leak of a native descriptor, which uses memory. */
    }
}

Then you can explain this is technically a memory leak, but really the leak is caused by native code in the JVM allocating underlying native resources, which weren't freed by your Java code.

At the end of the day, with a modern JVM, you need to write some Java code that allocates a native resource outside the normal scope of the JVM's awareness.

Answer 19

I thought it was interesting that no one used the internal class examples. If you have an internal class; it inherently maintains a reference to the containing class. Of course it is not technically a memory leak because Java WILL eventually clean it up; but this can cause classes to hang around longer than anticipated.

public class Example1 {
  public Example2 getNewExample2() {
    return this.new Example2();
  }
  public class Example2 {
    public Example2() {}
  }
}

Now if you call Example1 and get an Example2 discarding Example1, you will inherently still have a link to an Example1 object.

public class Referencer {
  public static Example2 GetAnExample2() {
    Example1 ex = new Example1();
    return ex.getNewExample2();
  }

  public static void main(String[] args) {
    Example2 ex = Referencer.GetAnExample2();
    // As long as ex is reachable; Example1 will always remain in memory.
  }
}

I've also heard a rumor that if you have a variable that exists for longer than a specific amount of time; Java assumes that it will always exist and will actually never try to clean it up if cannot be reached in code anymore. But that is completely unverified.

Answer 20

I recently encountered a memory leak situation caused in a way by log4j.

Log4j has this mechanism called Nested Diagnostic Context(NDC) which is an instrument to distinguish interleaved log output from different sources. The granularity at which NDC works is threads, so it distinguishes log outputs from different threads separately.

In order to store thread specific tags, log4j's NDC class uses a Hashtable which is keyed by the Thread object itself (as opposed to say the thread id), and thus till the NDC tag stays in memory all the objects that hang off of the thread object also stay in memory. In our web application we use NDC to tag logoutputs with a request id to distinguish logs from a single request separately. The container that associates the NDC tag with a thread, also removes it while returning the response from a request. The problem occurred when during the course of processing a request, a child thread was spawned, something like the following code:

pubclic class RequestProcessor {
    private static final Logger logger = Logger.getLogger(RequestProcessor.class);
    public void doSomething()  {
        ....
        final List<String> hugeList = new ArrayList<String>(10000);
        new Thread() {
           public void run() {
               logger.info("Child thread spawned")
               for(String s:hugeList) {
                   ....
               }
           }
        }.start();
    }
}    

So an NDC context was associated with inline thread that was spawned. The thread object that was the key for this NDC context, is the inline thread which has the hugeList object hanging off of it. Hence even after the thread finished doing what it was doing, the reference to the hugeList was kept alive by the NDC context Hastable, thus causing a memory leak.

Answer 21

Create a static Map and keep adding hard references to it. Those will never be garbage collected.

public class Leaker {
    private static final Map<String, Object> CACHE = new HashMap<String, Object>();

    // Keep adding until failure.
    public static void addToCache(String key, Object value) { Leaker.CACHE.put(key, value); }
}

Answer 22

Everyone always forgets the native code route. Here's a simple formula for a leak:

1. Declare a native method.
2. In the native method, call malloc. Don't call free.
3. Call the native method.

Remember, memory allocations in native code come from the JVM heap.

Answer 23

You can create a moving memory leak by creating a new instance of a class in that class's finalize method. Bonus points if the finalizer creates multiple instances. Here's a simple program that leaks the entire heap in sometime between a few seconds and a few minutes depending on your heap size:

class Leakee {
    public void check() {
        if (depth > 2) {
            Leaker.done();
        }
    }
    private int depth;
    public Leakee(int d) {
        depth = d;
    }
    protected void finalize() {
        new Leakee(depth + 1).check();
        new Leakee(depth + 1).check();
    }
}

public class Leaker {
    private static boolean makeMore = true;
    public static void done() {
        makeMore = false;
    }
    public static void main(String[] args) throws InterruptedException {
        // make a bunch of them until the garbage collector gets active
        while (makeMore) {
            new Leakee(0).check();
        }
        // sit back and watch the finalizers chew through memory
        while (true) {
            Thread.sleep(1000);
            System.out.println("memory=" +
                    Runtime.getRuntime().freeMemory() + " / " +
                    Runtime.getRuntime().totalMemory());
        }
    }
}

Answer 24

I came across a more subtle kind of resource leak recently. We open resources via class loader's getResourceAsStream and it happened that the input stream handles were not closed.

Uhm, you might say, what an idiot.

Well, what makes this interesting is: this way, you can leak heap memory of the underlying process, rather than from JVM's heap.

All you need is a jar file with a file inside which will be referenced from Java code. The bigger the jar file, the quicker memory gets allocated.

You can easily create such a jar with the following class:

import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class BigJarCreator {
    public static void main(String[] args) throws IOException {
        ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(new File("big.jar")));
        zos.putNextEntry(new ZipEntry("resource.txt"));
        zos.write("not too much in here".getBytes());
        zos.closeEntry();
        zos.putNextEntry(new ZipEntry("largeFile.out"));
        for (int i=0 ; i<10000000 ; i++) {
            zos.write((int) (Math.round(Math.random()*100)+20));
        }
        zos.closeEntry();
        zos.close();
    }
}

Just paste into a file named BigJarCreator.java, compile and run it from command line:

javac BigJarCreator.java
java -cp . BigJarCreator

Et voilà: you find a jar archive in your current working directory with two files inside.

Let's create a second class:

public class MemLeak {
    public static void main(String[] args) throws InterruptedException {
        int ITERATIONS=100000;
        for (int i=0 ; i<ITERATIONS ; i++) {
            MemLeak.class.getClassLoader().getResourceAsStream("resource.txt");
        }
        System.out.println("finished creation of streams, now waiting to be killed");

        Thread.sleep(Long.MAX_VALUE);
    }

}

This class basically does nothing, but create unreferenced InputStream objects. Those objects will be garbage collected immediately and thus, do not contribute to heap size. It is important for our example to load an existing resource from a jar file, and size does matter here!

If you're doubtful, try to compile and start the class above, but make sure to chose a decent heap size (2 MB):

javac MemLeak.java
java -Xmx2m -classpath .:big.jar MemLeak

You will not encounter an OOM error here, as no references are kept, the application will keep running no matter how large you chose ITERATIONS in the above example. The memory consumption of your process (visible in top (RES/RSS) or process explorer) grows unless the application gets to the wait command. In the setup above, it will allocate around 150 MB in memory.

If you want the application to play safe, close the input stream right where it's created:

MemLeak.class.getClassLoader().getResourceAsStream("resource.txt").close();

and your process will not exceed 35 MB, independent of the iteration count.

Quite simple and surprising.

Answer 25

I don't think anyone has said this yet: you can resurrect an object by overriding the finalize() method such that finalize() stores a reference of this somewhere. The garbage collector will only be called once on the object so after that the object will never destroyed.

Answer 26

Another way to create potentially huge memory leaks is to hold references to Map.Entry<K,V> of a TreeMap.

It is hard to asses why this applies only to TreeMaps, but by looking at the implementation the reason might be that: a TreeMap.Entry stores references to its siblings, therefore if a TreeMap is ready to be collected, but some other class holds a reference to any of its Map.Entry, then the entire Map will be retained into memory.

---

Real-life scenario:

Imagine having a db query that returns a big TreeMap data structure. People usually use TreeMaps as the element insertion order is retained.

public static Map<String, Integer> pseudoQueryDatabase();

If the query was called lots of times and, for each query (so, for each Map returned) you save an Entry somewhere, the memory would constantly keep growing.

Consider the following wrapper class:

class EntryHolder {
    Map.Entry<String, Integer> entry;

    EntryHolder(Map.Entry<String, Integer> entry) {
        this.entry = entry;
    }
}

Application:

public class LeakTest {

    private final List<EntryHolder> holdersCache = new ArrayList<>();
    private static final int MAP_SIZE = 100_000;

    public void run() {
        // create 500 entries each holding a reference to an Entry of a TreeMap
        IntStream.range(0, 500).forEach(value -> {
            // create map
            final Map<String, Integer> map = pseudoQueryDatabase();

            final int index = new Random().nextInt(MAP_SIZE);

            // get random entry from map
            for (Map.Entry<String, Integer> entry : map.entrySet()) {
                if (entry.getValue().equals(index)) {
                    holdersCache.add(new EntryHolder(entry));
                    break;
                }
            }
            // to observe behavior in visualvm
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        });

    }

    public static Map<String, Integer> pseudoQueryDatabase() {
        final Map<String, Integer> map = new TreeMap<>();
        IntStream.range(0, MAP_SIZE).forEach(i -> map.put(String.valueOf(i), i));
        return map;
    }

    public static void main(String[] args) throws Exception {
        new LeakTest().run();
    }
}

After each pseudoQueryDatabase() call, the map instances should be ready for collection, but it won't happen, as at least one Entry is stored somewhere else.

Depending on your jvm settings, the application may crash in the early stage due to a OutOfMemoryError.

You can see from this visualvm graph how the memory keeps growing.

The same does not happen with a hashed data-structure (HashMap).

This is the graph when using a HashMap.

The solution? Just directly save the key / value (as you probably already do) rather than saving the Map.Entry.

---

I have written a more extensive benchmark here.

Answer 27

As a lot of people have suggested, resource leaks are fairly easy to cause - like the JDBC examples. Actual memory leaks are a bit harder - especially if you aren't relying on broken bits of the JVM to do it for you...

The ideas of creating objects that have a very large footprint and then not being able to access them aren't real memory leaks either. If nothing can access it then it will be garbage collected, and if something can access it then it's not a leak...

One way that used to work though - and I don't know if it still does - is to have a three-deep circular chain. As in Object A has a reference to Object B, Object B has a reference to Object C and Object C has a reference to Object A. The GC was clever enough to know that a two deep chain - as in A <--> B - can safely be collected if A and B aren't accessible by anything else, but couldn't handle the three-way chain...

Answer 28

Threads are not collected until they terminate. They serve as roots of garbage collection. They are one of the few objects that won't be reclaimed simply by forgetting about them or clearing references to them.

Consider: the basic pattern to terminate a worker thread is to set some condition variable seen by the thread. The thread can check the variable periodically and use that as a signal to terminate. If the variable is not declared volatile, then the change to the variable might not be seen by the thread, so it won't know to terminate. Or imagine if some threads want to update a shared object, but deadlock while trying to lock on it.

If you only have a handful of threads these bugs will probably be obvious because your program will stop working properly. If you have a thread pool that creates more threads as needed, then the obsolete/stuck threads might not be noticed, and will accumulate indefinitely, causing a memory leak. Threads are likely to use other data in your application, so will also prevent anything they directly reference from ever being collected.

As a toy example:

static void leakMe(final Object object) {
    new Thread() {
        public void run() {
            Object o = object;
            for (;;) {
                try {
                    sleep(Long.MAX_VALUE);
                } catch (InterruptedException e) {}
            }
        }
    }.start();
}

Call System.gc() all you like, but the object passed to leakMe will never die.

Answer 29

The interviewer might have been looking for a circular reference solution:

    public static void main(String[] args) {
        while (true) {
            Element first = new Element();
            first.next = new Element();
            first.next.next = first;
        }
    }

This is a classic problem with reference counting garbage collectors. You would then politely explain that JVMs use a much more sophisticated algorithm that doesn't have this limitation.

Answer 30

I think that a valid example could be using ThreadLocal variables in an environment where threads are pooled.

For instance, using ThreadLocal variables in Servlets to communicate with other web components, having the threads being created by the container and maintaining the idle ones in a pool. ThreadLocal variables, if not correctly cleaned up, will live there until, possibly, the same web component overwrites their values.

Of course, once identified, the problem can be solved easily.

Answer 31

There are many different situations memory will leak. One I encountered, which expose a map that should not be exposed and used in other place.

public class ServiceFactory {

    private Map<String, Service> services;

    private static ServiceFactory singleton;

    private ServiceFactory() {
        services = new HashMap<String, Service>();
    }

    public static synchronized ServiceFactory getDefault() {

        if (singleton == null) {
            singleton = new ServiceFactory();
        }
        return singleton;
    }

    public void addService(String name, Service serv) {
        services.put(name, serv);
    }

    public void removeService(String name) {
        services.remove(name);
    }

    public Service getService(String name, Service serv) {
        return services.get(name);
    }

    // The problematic API, which exposes the map.
    // and user can do quite a lot of thing from this API.
    // for example, create service reference and forget to dispose or set it null
    // in all this is a dangerous API, and should not expose
    public Map<String, Service> getAllServices() {
        return services;
    }

}

// Resource class is a heavy class
class Service {

}

Answer 32

An example I recently fixed is creating new GC and Image objects, but forgetting to call dispose() method.

GC javadoc snippet:

Application code must explicitly invoke the GC.dispose() method to release the operating system resources managed by each instance when those instances are no longer required. This is particularly important on Windows95 and Windows98 where the operating system has a limited number of device contexts available.

Image javadoc snippet:

Application code must explicitly invoke the Image.dispose() method to release the operating system resources managed by each instance when those instances are no longer required.

Answer 33

A thread that does not terminate (say sleeps indefinitely in its run method). It will not be garbage collected even if we lose a reference to it. You can add fields to make the thread object is a big as you want.

The currently top answer lists more tricks around this, but these seem redundant.

Answer 34

I want to give advice on how to monitor an application for the memory leaks with the tools that are available in the JVM. It doesn't show how to generate the memory leak, but explains how to detect it with the minimum tools available.

You need to monitor Java memory consumption first.

The simplest way to do this is to use the jstat utility that comes with JVM:

jstat -gcutil <process_id> <timeout>

It will report memory consumption for each generation (young, eldery and old) and garbage collection times (young and full).

As soon as you spot that a full garbage collection is executed too often and takes too much time, you can assume that application is leaking memory.

Then you need to create a memory dump using the jmap utility:

jmap -dump:live,format=b,file=heap.bin <process_id>

Then you need to analyse the heap.bin file with a memory analyser, Eclipse Memory Analyzer (MAT) for example.

MAT will analyze the memory and provide you suspect information about memory leaks.

Answer 35

Theoretically you can't. The Java memory model prevents it. However, because Java has to be implemented, there are some caveats you can use. It depends on what you can use:

• If you can use native, you can allocate memory that you do not relinquish later.

• If that is not available, there is a dirty little secret about Java that not much people know. You can ask for a direct access array that is not managed by GC, and therefore can be easily used to make a memory leak. This is provided by DirectByteBuffer (http://download.oracle.com/javase/1.5.0/docs/api/java/nio/ByteBuffer.html#allocateDirect(int)).

• If you can't use any of those, you still can make a memory leak by tricking the GC. The JVM is implemented using a generational garbage collection. What this means is that the heap is divided into areas: young, adults and elders. An object when its created starts at the young area. As it is used more and more, it progresses into adults up to elders. An object that reaches the eldery area most likely will not be garbage collected. You cannot be sure that an object is leaked and if you ask for a stop and clean GC it may clean it, but for a long period of time it will be leaked. More information is at (http://java.sun.com/docs/hotspot/gc1.4.2/faq.html)

• Also, class objects are not required to be GC'ed. There might be a way to do it.

Answer 36

If the maximum heap size is X. Y1....Yn no of instances

So, total memory = number of instances X bytes per instance. If X1......Xn is bytes per instances, then total memory(M)=Y1 * X1+.....+Yn *Xn. So, if M>X, it exceeds the heap space.

The following can be the problems in code

1. Use of more instances variable then local one.
2. Creating instances every time instead of pooling object.
3. Not creating the object on demand.
4. Making the object reference null after the completion of operation. Again, recreating when it is demanded in program.

Answer 37

Throw an unhandled exception from the finalize method.

Answer 38

There are many answers on how to create a memory leak in Java, but please note the point asked during the interview.

"how to create a memory leak with Java?" is an open-ended question, whose purpose is to evaluate the degree of experience a developer has.

If I ask you "Do you have experience troubleshooting memory leaks in Java?", your answer would be a simple "Yes". I would have then to follow up with "Could you give me examples where you hat to troubleshoot memory leaks?", to which you would give me one or two examples.

However, when the interviewer asks "how to create a memory leak with Java?" the expected answer should follow alongs these lines:

• I've encountered a memory leak ... (say when) [that shows me experience]
• The code that was causing it was... (explain code) [you fixed it yourself]
• The fix I applied was based on ... (explain fix) [this gives me a chance to ask specifics about the fix]
• The test I did was ... [gives me the chance of asking other testing methodologies]
• I documented it this way ... [extra points. Good if you documented it]
• So, it is reasonable to think that, if we follow this in reverse order, which is, get the code I fixed, and remove my fix, that we would have a memory leak.

When the developer fails to follow this line of thought I try to guide him/her asking "Could you give me an example of how could Java leak memory?", followed by "Did you ever have to fix any memory leak in Java?"

Note that I am not asking for an example on how to leak memory in Java. That would be silly. Who would be interested in a developer who can effectively write code that leaks memory?

Answer 39

The String.substring method in Java 1.6 create a memory leak. This blog post explains it:

How SubString method works in Java - Memory Leak Fixed in JDK 1.7

Answer 40

Most of the memory leaks I've seen in Java concern processes getting out of sync.

Process A talks to B via TCP, and tells process B to create something. B issues the resource an ID, say 432423, which A stores in an object and uses while talking to B. At some point the object in A is reclaimed by garbage collection (maybe due to a bug), but A never tells B that (maybe another bug).

Now A doesn't have the ID of the object it's created in B's RAM any more, and B doesn't know that A has no more reference to the object. In effect, the object is leaked.

Answer 41

A few suggestions:

• use commons-logging in a servlet container (a bit provocative perhaps)
• start a thread in a servlet container and don't return from its run method
• load animated GIF images in a servlet container (this will start an animation thread)

The above effects could be 'improved' by redeploying the application ;)

I recently stumbled upon this:

• Calling "new java.util.zip.Inflater();" without calling "Inflater.end()" ever

Read http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=5072161 and linked issues for an in-depth-discussion.

Answer 42

A memory leak in Java is not your typical C/C++ memory leak.

To understand how the JVM works, read the Understanding Memory Management.

Basically, the important part is:

The Mark and Sweep Model

The JRockit JVM uses the mark and sweep garbage collection model for performing garbage collections of the whole heap. A mark and sweep garbage collection consists of two phases, the mark phase and the sweep phase.

During the mark phase all objects that are reachable from Java threads, native handles and other root sources are marked as alive, as well as the objects that are reachable from these objects and so forth. This process identifies and marks all objects that are still used, and the rest can be considered garbage.

During the sweep phase the heap is traversed to find the gaps between the live objects. These gaps are recorded in a free list and are made available for new object allocation.

The JRockit JVM uses two improved versions of the mark and sweep model. One is mostly concurrent mark and sweep and the other is parallel mark and sweep. You can also mix the two strategies, running for example mostly concurrent mark and parallel sweep.

So, to create a memory leak in Java; the easiest way to do that is to create a database connection, do some work, and simply not Close() it; then generate a new database connection while staying in scope. This isn't hard to do in a loop for example. If you have a worker that pulls from a queue and pushes to a database you can easily create a memory leak by forgetting to Close() connections or opening them when not necessary, and so forth.

Eventually, you'll consume the heap that has been allocated to the JVM by forgetting to Close() the connection. This will result in the JVM garbage collecting like crazy; eventually resulting in java.lang.OutOfMemoryError: Java heap space errors. It should be noted that the error may not mean there is a memory leak; it could just mean you don't have enough memory; databases like Cassandra and Elasticsearch for example can throw that error because they don't have enough heap space.

It's worth noting that this is true for all GC languages. Below, are some examples I've seen working as an SRE:

• Node.js using Redis as a queue; the development team created new connections every 12 hours and forgot to close the old ones. Eventually node was OOMd because it consumed all the memory.
• Go (I'm guilty of this one); parsing large JSON files with json.Unmarshal and then passing the results by reference and keeping them open. Eventually, this resulted in the entire heap being consumed by accidental references I kept open to decode JSON.

Answer 43

One possibility is to create a wrapper for an ArrayList that only provides one method: one that adds things to the ArrayList. Make the ArrayList itself private. Now, construct one of these wrapper objects in global scope (as a static object in a class) and qualify it with the final keyword (e.g. public static final ArrayListWrapper wrapperClass = new ArrayListWrapper()). So now the reference cannot be altered. That is, wrapperClass = null won't work and can't be used to free the memory. But there's also no way to do anything with wrapperClass other than add objects to it. Therefore, any objects you do add to wrapperClass are impossible to recycle.

Answer 44

In Java a "memory leak" is primarily just you using too much memory which is different than in C where you are no longer using the memory but forget to return (free) it. When an interviewer asks about Java memory leaks they are asking about JVM memory usage just appearing to keep going up and they determined that restarting the JVM on a regular basis is the best fix (unless the interviewer is extremely technically savvy).

So answer this question as if they asked what makes JVM memory usage grow over time. Good answers would be storing too much data in a HttpSessions with overly long timeout or a poorly implemented in-memory cache (singleton) that never flushes old entries. Another potential answer is having lots of JSPs or dynamically generated classes. Classes are loaded into an area of memory called PermGen that is usually small and most JVMs don't implement class unloading.

Answer 45

Swing has it very easy with dialogs. Create a JDialog, show it, the user closes it, and leak!

You have to call dispose() or configure setDefaultCloseOperation(DISPOSE_ON_CLOSE).

Answer 46

If you don't use a compacting garbage collector, you can have some sort of a memory leak due to heap fragmentation.

Answer 47

Lapsed Listerners is a good example of memory leaks: Object is added as a Listener. All references to the object are nulled when the object is not needed anymore. However, forgetting to remove the object from the Listener list keeps the object alive and even responding to events, thereby wasting both memory and CPU. See http://www.drdobbs.com/jvm/java-qa/184404011

Answer 48

Carelessly using a non-static inner class inside a class which has its own life cycle.

In Java, non-static inner and anonymous classes hold an implicit reference to their outer class. Static inner classes, on the other hand, do not.

Here is a common example to have memory leak in Android, which is not obvious though:

public class SampleActivity extends Activity {

  private final Handler mLeakyHandler = new Handler() { // Non-static inner class, holds the reference to the SampleActivity outer class
    @Override
    public void handleMessage(Message msg) {
      // ...
    }
  }

  @Override
  protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    // Post a message and delay its execution for a long time.
    mLeakyHandler.postDelayed(new Runnable() {//here, the anonymous inner class holds the reference to the SampleActivity class too
      @Override
      public void run() {
     //....
      }
    }, SOME_TOME_TIME);

    // Go back to the previous Activity.
    finish();
  }}

This will prevent the activity context from being garbage collected.

Answer 49

import sun.misc.Unsafe;
import java.lang.reflect.Field;

public class Main {
    public static void main(String args[]) {
        try {
            Field f = Unsafe.class.getDeclaredField("theUnsafe");
            f.setAccessible(true);
            ((Unsafe) f.get(null)).allocateMemory(2000000000);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

Answer 50

There are many good examples of memory leaks in Java, and I will mention two of them in this answer.

Example 1:

Here is a good example of a memory leak from the book Effective Java, Third Edition (item 7: Eliminate obsolete object references):

// Can you spot the "memory leak"?
public class Stack {
    private static final int DEFAULT_INITIAL_CAPACITY = 16;
    private Object[] elements;
    private int size = 0;

    public Stack() {
        elements = new Object[DEFAULT_INITIAL_CAPACITY];
    }

    public void push(Object e) {
        ensureCapacity();
        elements[size++] = e;
    }

    public Object pop() {
        if (size == 0) throw new EmptyStackException();
        return elements[--size];
    }

    /*** Ensure space for at least one more element, roughly* doubling the capacity each time the array needs to grow.*/
    private void ensureCapacity() {
        if (elements.length == size) elements = Arrays.copyOf(elements, 2 * size + 1);
    }
}

This is the paragraph of the book that describes why this implementation will cause a memory leak:

If a stack grows and then shrinks, the objects that were popped off the stack will not be garbage collected, even if the program using the stack has no more references to them. This is because the stack maintains obsolete references to these objects. An obsolete reference is simply a reference that will never be dereferenced again. In this case, any references outside of the “active portion” of the element array are obsolete. The active portion consists of the elements whose index is less than size

Here is the solution of the book to tackle this memory leak:

The fix for this sort of problem is simple: null out references once they become obsolete. In the case of our Stack class, the reference to an item becomes obsolete as soon as it’s popped off the stack. The corrected version of the pop method looks like this:

public Object pop() {
    if (size == 0) throw new EmptyStackException();
    Object result = elements[--size];
    elements[size] = null; // Eliminate obsolete reference
    return result;
}

But how can we prevent a memory leak from happening? This is a good caveat from the book:

Generally speaking, whenever a class manages its own memory, the programmer should be alert for memory leaks. Whenever an element is freed, any object references contained in the element should be nulled out.

Example 2:

The observer pattern also can cause a memory leak. You can read about this pattern in the following link: Observer pattern.

This is one implementation of the Observer pattern:

class EventSource {
    public interface Observer {
        void update(String event);
    }

    private final List<Observer> observers = new ArrayList<>();

    private void notifyObservers(String event) {
        observers.forEach(observer -> observer.update(event)); //alternative lambda expression: observers.forEach(Observer::update);
    }

    public void addObserver(Observer observer) {
        observers.add(observer);
    }

    public void scanSystemIn() {
        Scanner scanner = new Scanner(System.in);
        while (scanner.hasNextLine()) {
            String line = scanner.nextLine();
            notifyObservers(line);
        }
    }
}

In this implementation, EventSource, which is Observable in the Observer design pattern, can hold link to Obeserver objects, but this link is never removed from the observers field in EventSource. So they will never be collected by the garbage collector. One solution to tackle this problem is providing another method to the client for removing the aforementioned observers from the observers field when they don't need those observers any more:

public void removeObserver(Observer observer) {
    observers.remove(observer);
}

Answer 51

a memory leak is a type of resource leak that occurs when a computer program incorrectly manages memory allocations in such a way that memory which is no longer needed is not released => Wikipedia definition

_{It's kind of relatively context-based topic, you can just create one based on your taste as long as the unused references will never be used by clients, but still stay alive.}

The first example should be a custom stack without nulling the obsolete references in Effective Java, item 6.

Of course there are many more as long as you want, but if we just take look at the Java built-in classes, it could be some as

subList()

Let's check some super silly code to produce the leak.

public class MemoryLeak {
    private static final int HUGE_SIZE = 10_000;

    public static void main(String... args) {
        letsLeakNow();
    }

    private static void letsLeakNow() {
        Map<Integer, Object> leakMap = new HashMap<>();
        for (int i = 0; i < HUGE_SIZE; ++i) {
            leakMap.put(i * 2, getListWithRandomNumber());
        }
    }



    private static List<Integer> getListWithRandomNumber() {
        List<Integer> originalHugeIntList = new ArrayList<>();
        for (int i = 0; i < HUGE_SIZE; ++i) {
            originalHugeIntList.add(new Random().nextInt());
        }
        return originalHugeIntList.subList(0, 1);
    }
}

Actually there is another trick we can cause memory leak using HashMap by taking advantage of its looking process. There are actually two types:

• hashCode() is always the same but equals() are different;
• use random hashCode() and equals() always true;

Why?

hashCode() -> bucket => equals() to locate the pair

---

I was about to mention substring() first and then subList() but it seems this issue is already fixed as its source presents in JDK 8.

public String substring(int beginIndex, int endIndex) {
    if (beginIndex < 0) {
        throw new StringIndexOutOfBoundsException(beginIndex);
    }
    if (endIndex > value.length) {
        throw new StringIndexOutOfBoundsException(endIndex);
    }
    int subLen = endIndex - beginIndex;
    if (subLen < 0) {
        throw new StringIndexOutOfBoundsException(subLen);
    }
    return ((beginIndex == 0) && (endIndex == value.length)) ? this
            : new String(value, beginIndex, subLen);
}

Answer 52

A real-time example of a memory leak before JDK 1.7:

Suppose you read a file of 1000 lines of text and keep them in String objects:

String fileText = 1000 characters from file

fileText = fileText.subString(900, fileText.length());

In above code I initially read 1000 characters and then did substring to get only the 100 last characters. Now fileText should only refer to 100 characters and all other characters should get garbage collected as I lost the reference, but before JDK 1.7 the substring function indirectly referred to the original string of last 100 characters and prevents the whole string from garbage collection and the whole 1000 characters will be there in memory until you lose reference of the substring.

You can create memory leak example like the above.

Answer 53

One of the Java memory leakings examples is MySQLs memory leaking bug resulting when ResultSets close method is forgotten to be called. For example:

while(true) {
    ResultSet rs = database.select(query);
    ...
    // going to next step of loop and leaving resultset without calling rs.close();
}

Answer 54

Create a JNI function containing just a while-true loop and call it with a large object from another thread. The GC doesn't like JNI very much and is going to keep the object in memory forever.

Answer 55

One of the easiest ways to implement a memory leak sample is to use a static method.

For example,

static List<int> list = new ArrayList<>();
for (int i = 0; i < 10000; i++) {
    list.add(i);
}

system.sleep();

In this case, the JVM can't release the memory of list, cuz it's a static class and it always remains memory on heap.

Answer 56

From the Effective Java book (by Joshua Bloch):

1. Whenever a class manages its own memory, the programmer should be alert for memory leaks

   public class Stack {
   
       private Object[] elements;
       private int size = 0;
       private static final int DEFAULT_INITIAL_CAPACITY = 16;
   
       public Stack() {
           elements = new Object[DEFAULT_INITIAL_CAPACITY];
       }
   
       public void push(Object e) {
           ensureCapacity();
           elements[size++] = e;
       }
   
       public Object pop() {
           if (size == 0)
               throw new EmptyStackException();
           return elements[--size];
       }
   
       /**
        * Ensure space for at least one more element, roughly doubling the capacity
        * each time the array needs to grow.
        */
       private void ensureCapacity() {
           if (elements.length == size)
               elements = Arrays.copyOf(elements, 2 * size + 1);
       }
   }
   

Can you spot the memory leak? So where is the memory leak? If a stack grows and then shrinks, the objects that were popped off the stack will not be garbage collected, even if the program using the stack has no more references to them.

This is because the stack maintains obsolete references to these objects. An obsolete reference is simply a reference that will never be dereferenced again. In this case, any references outside of the “active portion” of the element array are obsolete. The active portion consists of the elements whose index is less than size.

Answer 57

Here is a very simple Java program that will run out of space

public class OutOfMemory {

    public static void main(String[] arg) {

        List<Long> mem = new LinkedList<Long>();
        while (true) {
            mem.add(new Long(Long.MAX_VALUE));
        }
    }
}

Answer 58

There's no such thing as a memory leak in Java. Memory leak is a phrase borrowed from C et al. Java deals with memory allocation internally with the help of the GC. There's memory wastefulness (ie. leaving stranded objects), but not memory leak.

Answer 59

Just like this!

public static void main(String[] args) {
    List<Object> objects = new ArrayList<>();
    while(true) {
        objects.add(new Object());
    }
}