Setting values to parameters in a constructor in Java

Question

I just wanted to ask basically what the title says. Here's my example and I want x to be the new set random. I also am doing this off a phone switch doesn't support an equal sign so - means equal. Also the bracket is (. So when I do Constructor a - new Constructor(x)

public class Opponent (

    public static x - 0;

    public Opponent (int value) (
        value - 5;
    )

    public static void main (String() args) (
        Opponent character1 - new Opponent(x)
        System.out.println(x);
    )
)

Basically I want x to become 5. The game I am developing concerns randomization then the values should give them to the parameter to the newly created character.

Problem I am having is that its not working which means it probably can't do this.

Is there anyway I can do this.

I apologize if it is a dumb question though but anyways thanks.

This is very basic stuff. Not only your question, but the syntax for anything you wrote. Please, look up some tutorials and learn some givens before you ask a question like this. — Michael Yaworski, Nov 21 '13 at 02:24
Yep, the correct answer to this question: you will want to study a decent Java text or two. It's how I (and many others) started in this language, and if it worked well for us, it will work well for you! — Hovercraft Full Of Eels, Nov 21 '13 at 02:43

Michael Yaworski · Answer 1 · 2013-12-23T03:05:00.137

public class Opponent {

    public static int x = 0;

    public Opponent (int value) {
        x = value;
    }

    public static void main (String[] args) {
        int y = 5; // random number I chose to be 5
        Opponent character1 = new Opponent(y);
        System.out.println(character1.x + ""); // will display 5 (which was int y)
    }
}

List of Problems:

• To open/close a method/class, don't use ( and ); you have to use { and }

• public static void main (String() args) needs to be
public static void main (String[] args)

• To initialize something, use =, not -.

• You need to give x a type, such as int.

• When you defined Opponent character1 - new Opponent(x), you need to have a semi-colon at the end.

• You passed x as a parameter in the line Opponent character1 = new Opponent(y);, even though you were trying to define x with the parameter. Give it a different value.

One note: why would you define an instance of the class in the class? Instead of using this:

Opponent character1 = new Opponent(y);
System.out.println(character1.x + "");

You could just write this:

System.out.println(Opponent.x + "");

However, you could create character1 if you were accessing class Opponent from a different class.

Michael · Answer 2 · 2013-11-21T02:49:28.523

0

I honestly don't know what your question is, but try running this:

public class Opponent {

    public int x;

    public Opponent (int value) {
        x = value;
    }

    public static void main (String[] args) {
        Opponent character1 = new Opponent(5);
        System.out.println(character1.x); // this will output: 5
    }
}

A few problems with your question:

you are trying to initialize a static variable thinking its an instance variable?
x is not initialized in main()
value is not defined as a field in Opponent

edited Nov 21 '13 at 02:49

answered Nov 21 '13 at 02:43

Michael

413
2
8

Thanks for the comments. Like I said though that I am typing from a phone and cannot use most symbols. – Abszol Nov 21 '13 at 12:46

score -1 · Answer 3 · edited May 23 '17 at 11:54

maybe something like this. i leave the random number generation up to you:

public class Opponent
{
    private int score;

    public Opponent()
    {
        // you probbaly want to override this with
        // a random number generator
        this.score = 0;
    }

    public Opponent(int value)
    {
        this.score = value;
    }

    public int getScore()
    {
        return this.score;
    }

    public void setScore(int score)
    {
        this.score = score;
    }

    public static void main(String[] args)
    {
        Opponent character1 = new Opponent();
        Opponent character2 = new Opponent(5);

        int result = character1.getScore() - character2.getScore();
        System.out.println(result);
    }
}

Setting values to parameters in a constructor in Java

3 Answers3