Using VS2008, why is this OK (not allowed to use 2010).
void assert(int exp, int actual) {if (exp!=actual) printf("assert failed\n");}
void assert(unsigned int exp, unsigned int actual) {if (exp!=actual) printf("assert failed\n");}
But this is ambiguous.
void assert(__int64 exp, __int64 actual) {if (exp!=actual) printf("assert failed\n");}
void assert(unsigned __int64 exp, unsigned __int64 actual) {if (exp!=actual) printf("assert failed\n");}
Sample error text
d:\my documents\visual studio 2008\projects\classtest\classtest\classtest.cpp(31) : error C2668: 'assert' : ambiguous call to overloaded function
d:\my documents\visual studio 2008\projects\classtest\classtest\classtest.cpp(12): could be 'void assert(unsigned __int64,unsigned __int64)'
d:\my documents\visual studio 2008\projects\classtest\classtest\classtest.cpp(10): or 'void assert(__int64,__int64)'
while trying to match the argument list '(int, int)'
It only gets ambiguous with regards to the 'unsigned' overload. Having and "int" version and an "__int64" version is not ambiguous.