Remove an item from an array by value

Question

I have an array of items like:

var items = [id: "animal", type: "cat", cute: "yes"]

And I'm trying to remove any items that match the ID given. In this case; animal

I'm stuck! I can get it to work easily by having a more simpler array but this is not what I need... I also need to remove the item by value as I don't want the hassle of referring to items by their index.

Is there a jQuery method I could use where I don't need to iterate through the items array, rather specify a selector?

Here is my jsFiddle: http://jsfiddle.net/zafrX/

Your syntax is invalid. Do you have an array or an object? You have mixed the syntax. — James Montagne, Jan 15 '12 at 21:46
If you look in the javascript console (firebug, in my case), it raised that error, 'Uncaught SyntaxError: Unexpected token :' You should create an object Item, and you will be able to access easily attributes of the Item — Jeremy D, Jan 15 '12 at 21:47
object `var items = { id: "animal", type: "cat", cute: "yes" }`, array `var items = ["animal", "cat", "yes" ]` — Lautaro Orazi, Jan 15 '12 at 21:51

Adam Rackis · Accepted Answer · 2012-01-15T22:03:54.640

I'm not sure how much of a hassle it is to refer to array items by index. The standard way to remove array items is with the splice method

for (var i = 0; i < items.length; i++)
    if (items[i] === "animal") { 
        items.splice(i, 1);
        break;
    }

And of course you can generalize this into a helper function so you don't have to duplicate this everywhere.

EDIT

I just noticed this incorrect syntax:

var items = [id: "animal", type: "cat", cute: "yes"]

Did you want something like this:

 var items = [ {id: "animal",  type: "cat", cute: "yes"}, {id: "mouse",  type: "rodent", cute: "no"}];

That would change the removal code to this:

for (var i = 0; i < items.length; i++)
    if (items[i].id && items[i].id === "animal") { 
        items.splice(i, 1);
        break;
    }

items.splice(items.indexOf("animals"), 1) – Paully May 22 '19 at 20:27 — Paully, May 22 '19 at 20:27

score 11 · Answer 2 · answered Oct 05 '17 at 16:14

11

No need for jQuery or any third party lib for this, now we can use the new ES5 filter :

let myArray = [{ id : 'a1', name : 'Rabbit'}, { id : 'a2', name : 'Cat'}];
myArray = myArray.filter(i => i.id !== 'a1');

answered Oct 05 '17 at 16:14

Chtiwi Malek

9,757
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65

Milad Naseri · Answer 3 · 2017-11-04T18:45:18.153

6

You can either use splice or run a delete yourself. Here's an example:

for (var i = 0; i < items.length; i ++) {
    if (items[i] == "animal") { 
        items.splice(i, 1);
        break;
    }
}

edited Nov 04 '17 at 18:45

answered Jan 15 '12 at 21:46

Milad Naseri

3,875
1
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score 5 · Answer 4 · edited Sep 08 '18 at 16:01

There's a simple way!

myItems.splice(myItems.indexOf(myItems.find(row => row.id == id)), 1);

Demo below:

// define function
function delete_by_id(id) {

  var myItems = [{
    id: 1,
    type: "cat",
    cute: "yes"
  }, {
    id: 2,
    type: "rat",
    cute: "yes"
  }, {
    id: 3,
    type: "mouse",
    cute: "yes"
  }];

  // before
  console.log(myItems);

  myItems.splice(myItems.indexOf(myItems.find(item => item.id == id)), 1);

  // after 
  console.log(myItems);

}

// call function
delete_by_id(1);

Aleksandar Vucetic · Answer 5 · 2012-01-15T22:11:07.257

3

You should do it like this (make sure that you have the right syntax...you cannot have array with properties, but object inside {} and then you can iterate by keys and delete unwanted key):

var items = {id: "animal", type: "cat", cute: "yes"}
var removeItem = "animal"; // or with the ID matching animal...

for(var p in items){
    if(items[p] === removeItem)
        delete items[p]
}

And to answer you question, you cannot apply jquery selectors to javascript objects. The best you can do to avoid for loop is to use $.each (which is a loop written in a more "functional" way).

edited Jan 15 '12 at 22:11

answered Jan 15 '12 at 21:55

Aleksandar Vucetic

13,899
7
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I think this might be the right answer. I missed OP's incorrect syntax. – Adam Rackis Jan 15 '12 at 22:02

score 2 · Answer 6 · edited Nov 07 '14 at 09:51

By using object notation : http://jsfiddle.net/jrm2k6/zafrX/2/

var animal1 = {id: "animal", type: "cat", cute: "yes"}
var car2 = {id: "car", type: "pick-up", cute: "no"}
var animal3 = {id: "animal", type: "dog", cute: "yes"}
var removeItem = "animal"; // or with the ID matching animal...

var array_items = []
array_items.push(animal1);
array_items.push(car2);
array_items.push(animal3);

for(var i=0;i<array_items.length;i++){
    if(array_items[i].id == removeItem){
        array_items.splice(i,1);
    }
}

//alert(array_items.length);

score 0 · Answer 7 · edited May 23 '17 at 10:29

0

Wow, so many ideas but still not what I wanted xD

This will remove ALL entries of the given value and return the removed value:

function removeOfArray(val, arr){
    var idx;
    var ret;
    while ((idx = arr.indexOf(val)) > -1){
        arr.splice(idx, 1);
        ret = val;
    }
    return ret;
}

Also I found other solutions here: Remove item from array by value

edited May 23 '17 at 10:29

Community

1
1

answered Aug 07 '14 at 13:10

Möhre

819
1
5
14

R Maharajan · Answer 8 · 2019-10-09T07:05:26.307

-parray : list of array of object
-pstring :value to remove from the array
-ptag :using which tag we

function removeFromArr (parray,ptag,pstring){
 var b =[];
var count = 0;
for (var i =0;i<parray.length;i++){
 if(pstring != parray[i][ptag]){
 b[count] = parray[i];
 count++;
 }
}
 return b;
}

var lobj = [ {
 "SCHEME_CODE": "MIP65",
 "YEARS": "1",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "1.80",
 "FREQUENCY": "Monthly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "1.79"
 },
 {
 "SCHEME_CODE": "MIP65",
 "YEARS": "2",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "1.98",
 "FREQUENCY": "Monthly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "1.96"
 },
 {
 "SCHEME_CODE": "MIP65",
 "YEARS": "3",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "2.05",
 "FREQUENCY": "Monthly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "2.03"
 },
 {
 "SCHEME_CODE": "MIP65",
 "YEARS": "5",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "2.26",
 "FREQUENCY": "Monthly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "2.24"
 },
 {
 "SCHEME_CODE": "QIP65",
 "YEARS": "1",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "1.80",
 "FREQUENCY": "Quarterly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "1.79"
 },
 {
 "SCHEME_CODE": "QIP65",
 "YEARS": "2",
 "CURRENCY": "GBP",
 "MAX_AMT": 200000,
 "MIN_AMT": 1000,
 "AER_IR": "1.98",
 "FREQUENCY": "Quarterly",
 "CUST_TYPE": "RETAIL",
 "GROSS_IR": "1.97"
 },
]

function myFunction(){
 var final = removeFromArr(lobj,"SCHEME_CODE","MIP65");
 console.log(final);
}

<html>
<button onclick="myFunction()">Click me</button>
</html>

are going to remove from the objects

function removeFromArr(parray, pstring, ptag) {
        var farr = [];
        var count = 0;
        for (var i = 0; i < pa.length; i++) {
            if (pstring != pa[i][ptag]) {
                farr[count] = pa[i];
                count++;
            }
        }
        return farr;
    }

Please include an explanation of how and why this solves the problem would really help to improve the quality of your post. — Saeed Zhiany, Oct 09 '19 at 06:54

score 0 · Answer 9 · answered Sep 23 '20 at 16:47

0

ES6 Solution

persons.splice(persons.findIndex((pm) => pm.id === personToDelete.id), 1);

answered Sep 23 '20 at 16:47

ThomasP1988

3,201
2
24
30

Remove an item from an array by value

9 Answers9