Minify multiple files with UglifyJS

Question

Is it possible to compress multiple files with UglifyJS?

Something like...

uglifyjs -o app.build.js appfile1.js appfile2.js ...

Also, I am running Uglify via NodeJS in Windows Command Prompt

Jakub · Accepted Answer · 2012-01-11T02:07:24.797

52

Actually what you want to do (trick it into thinking its just 1 file) is just cat it

Linux

cat file1.js file2.js file3.js file4.js | uglifyjs -o files.min.js

Windows (untested)

type file1.js file2.js > uglifyjs -o files.min.js

OR

type file1.js file2.js > merged.files.js
uglifyjs -o merged.files.js

edited Jan 11 '12 at 02:07

answered Jan 11 '12 at 00:41

Jakub

19,870
8
62
92

Guess I should have mentioned I am on windows... :( – jcreamer898 Jan 11 '12 at 00:43
Err... this might work then (not tested by me of course) http://stackoverflow.com/a/60254/158014 – Jakub Jan 11 '12 at 00:44
I updated my answer with windows syntax, I hope that works, as I haven't tested it, but that *should* be it... – Jakub Jan 11 '12 at 02:07
U just made my day! Works perfectly. – Michael Dausmann Jul 24 '12 at 23:33
This approach is bad, because it doesn't allow you to have source maps, pointing at your original sources. Luckily, with UglifyJS2, we don't need this anymore. – Boris Burkov Feb 19 '17 at 10:51
If you're on windows you are on ubuntu now. Look up Ubuntu bash on windows. It's very nice. – Andrew Jan 29 '18 at 02:52

score 41 · Answer 2 · answered Nov 21 '13 at 17:59

41

For future readers of this question, w/ UglifyJS2, this is trivial now...

uglifyjs file1.js file2.js -o foo.min.js

There is also support for source maps too.

uglifyjs file1.js file2.js -o foo.min.js --source-map foo.min.js.map --source-map-root http://foo.com/src

answered Nov 21 '13 at 17:59

jcreamer898

7,809
4
39
55

3

You can also use * to combine all JS files from a directory into a single file" `uglifyjs -o test.js /someTestDir/*` The docs say that the options should be first, and the files last; but these examples show the opposite. To quote https://github.com/mishoo/UglifyJS "filename should be the last argument and should name the file from which to read the JavaScript code" Does it not matter, or is this answer incorrect? – JeffryHouser Jan 10 '14 at 14:20
2

Just to add a a clarification to my previous comment, the * trick appears to be specific to Git Bash and is unrelated to UglifyJS. – JeffryHouser Jan 11 '14 at 01:10

score 3 · Answer 3 · answered Sep 25 '14 at 23:03

No.

but as other answers states, in it current form, it can concatenate all of them in the same output. Which is not the same as is being asked.

If you have a dozen files that are individual modules. You can not uglify them all at the same time. Which is desirable because you save build time to start nodejs every time.

yuicompressor allows this, and the time saved by not starting up a jvm for each individual file is great. And in the end you do get file1-min.js, file2-min.js, etc... not one concatenated blob.

With uglify you will have to spawn one process per file if you do not want to concatenate output.

Minify multiple files with UglifyJS

3 Answers3

Linked