How to add url parameter to the current url?

Question

Currently I'm at

http://example.com/topic.php?id=14

and I want to make a link to

http://example.com/topic.php?id=14&like=like

by not defining the current url. Like <a href="&like=like">Like</a>. However this last one shows me http://example.com/&like=like

Possible dupe of http://stackoverflow.com/questions/486896/adding-a-parameter-to-the-url-with-javascript or http://stackoverflow.com/questions/6899097/how-to-add-a-parameter-to-the-url — reflexiv, Jul 16 '13 at 05:46

score 20 · Accepted Answer · answered Dec 19 '11 at 14:19

20

There is no way to write a relative URI that preserves the existing query string while adding additional parameters to it.

You have to:

topic.php?id=14&like=like

answered Dec 19 '11 at 14:19

Quentin

800,325
104
1,079
1,205

3

There are many ways. See http://stackoverflow.com/questions/6899097/how-to-add-a-parameter-to-the-url for how to using Javascript. – reflexiv Jul 16 '13 at 05:41
6

You don't need to repeat the path. Starting with ? is okay. http://stackoverflow.com/q/7871871/62421 – webjunkie Jul 21 '16 at 10:40
1

What about using `` ? – rambodrahmani May 13 '20 at 09:14
@rambodrahmani — This isn't a PHP question and that is vulnerable to XSS attacks. – Quentin May 13 '20 at 09:48

score 16 · Answer 2 · answered Dec 19 '11 at 14:23

function currentUrl() {
    $protocol = strpos(strtolower($_SERVER['SERVER_PROTOCOL']),'https') === FALSE ? 'http' : 'https';
    $host     = $_SERVER['HTTP_HOST'];
    $script   = $_SERVER['SCRIPT_NAME'];
    $params   = $_SERVER['QUERY_STRING'];

    return $protocol . '://' . $host . $script . '?' . $params;
}

Then add your value with something like;

echo currentUrl().'&value=myVal';

score 12 · Answer 3 · answered Jan 17 '17 at 17:10

12

I know I'm late to the game, but you can just do ?id=14&like=like by using http build query as follows:

http_build_query(array_merge($_GET, array("like"=>"like")))

Whatever GET parameters you had will still be there and if like was a parameter before it will be overwritten, otherwise it will be included at the end.

answered Jan 17 '17 at 17:10

Zachary Weixelbaum

814
9
22

1

This is php only – Overflow Jan 31 '19 at 15:52
You are correct, and I can't believe I didn't realize this question wasn't a PHP question. I just assumed it was because another answer was also given in PHP :/ – Zachary Weixelbaum Feb 01 '19 at 17:04

score 5 · Answer 4 · answered May 10 '19 at 17:04

In case you want to add the URL parameter in JavaScript, see this answer. As suggested there, you can use the URLSeachParams API in modern browsers as follows:

<script>
function addUrlParameter(name, value) {
  var searchParams = new URLSearchParams(window.location.search)
  searchParams.set(name, value)
  window.location.search = searchParams.toString()
}
</script>

<body>
...
  <a onclick="addUrlParameter('like', 'like')">Like this page</a>
...
</body>

score 2 · Answer 5 · answered Dec 19 '11 at 14:21

2

If you wish to use "like" as a parameter your link needs to be:

<a href="/topic.php?like=like">Like</a>

More likely though is that you want:

<a href="/topic.php?id=14&like=like">Like</a>

answered Dec 19 '11 at 14:21

span

5,144
5
47
96

Kamil Kiełczewski · Answer 6 · 2020-05-13T16:11:23.140

1

It is not elegant but possible to do it as one-liner <a> element

<a href onclick="event.preventDefault(); location+='&like=like'">Like</a>

edited May 13 '20 at 16:11

answered Mar 16 '20 at 14:40

Kamil Kiełczewski

53,729
20
259
241

score 0 · Answer 7 · answered Sep 10 '16 at 02:28

Maybe you can write a function as follows:

var addParams = function(key, val, url) {
  var arr = url.split('?');
  if(arr.length == 1) {
    return url + '?' + key + '=' + val;
  }
  else if(arr.length == 2) {
    var params = arr[1].split('&');
    var p = {};
    var a = [];
    var strarr = [];
    $.each(params, function(index, element) {
      a = element.split('=');
      p[a[0]] = a[1];
      })
    p[key] = val;
    for(var o in p) {
      strarr.push(o + '=' + p[o]);
    }
    var str = strarr.join('&');
    return(arr[0] + '?' + str);
  }
}

How to add url parameter to the current url?

7 Answers7

Linked

Related