How do I unbind "hover" in jQuery?

Question

How do I unbind "hover" in jQuery?

This does not work:

$(this).unbind('hover');

Answer 1

$(this).unbind('mouseenter').unbind('mouseleave')

or more succinctly (thanks @Chad Grant):

$(this).unbind('mouseenter mouseleave')

Answer 2

Actually, the jQuery documentation has a more simple approach than the chained examples shown above (although they'll work just fine):

$("#myElement").unbind('mouseenter mouseleave');

As of jQuery 1.7, you are also able use $.on() and $.off() for event binding, so to unbind the hover event, you would use the simpler and tidier:

$('#myElement').off('hover');

The pseudo-event-name "hover" is used as a shorthand for "mouseenter mouseleave" but was handled differently in earlier jQuery versions; requiring you to expressly remove each of the literal event names. Using $.off() now allows you to drop both mouse events using the same shorthand.

Edit 2016:

Still a popular question so it's worth drawing attention to @Dennis98's point in the comments below that in jQuery 1.9+, the "hover" event was deprecated in favour of the standard "mouseenter mouseleave" calls. So your event binding declaration should now look like this:

$('#myElement').off('mouseenter mouseleave');

Answer 3

Unbind the mouseenter and mouseleave events individually or unbind all events on the element(s).

$(this).unbind('mouseenter').unbind('mouseleave');

or

$(this).unbind();  // assuming you have no other handlers you want to keep

Answer 4

unbind() doesn't work with hardcoded inline events.

So, for example, if you want to unbind the mouseover event from <div id="some_div" onmouseover="do_something();">, I found that $('#some_div').attr('onmouseover','') is a quick and dirty way to achieve it.

Answer 5

Another solution is .die() for events who that attached with .live().

Ex.:

// attach click event for <a> tags
$('a').live('click', function(){});

// deattach click event from <a> tags
$('a').die('click');

You can find a good refference here: Exploring jQuery .live() and .die()

( Sorry for my english :"> )

Answer 6

You can remove a specific event handler that was attached by on, using off

$("#ID").on ("eventName", additionalCss, handlerFunction);

// to remove the specific handler
$("#ID").off ("eventName", additionalCss, handlerFunction);

Using this, you will remove only handlerFunction
Another good practice, is to set a nameSpace for multiple attached events

$("#ID").on ("eventName1.nameSpace", additionalCss, handlerFunction1);
$("#ID").on ("eventName2.nameSpace", additionalCss, handlerFunction2);
// ...
$("#ID").on ("eventNameN.nameSpace", additionalCss, handlerFunctionN);

// and to remove handlerFunction from 1 to N, just use this
$("#ID").off(".nameSpace");

Answer 7

All hover is doing behind the scenes is binding to the mouseover and mouseout property. I would bind and unbind your functions from those events individually.

For example, say you have the following html:

<a href="#" class="myLink">Link</a>

then your jQuery would be:

$(document).ready(function() {

  function mouseOver()
  {
    $(this).css('color', 'red');
  }
  function mouseOut()
  {
    $(this).css('color', 'blue');
  }

  // either of these might work
  $('.myLink').hover(mouseOver, mouseOut); 
  $('.myLink').mouseover(mouseOver).mouseout(mouseOut); 
  // otherwise use this
  $('.myLink').bind('mouseover', mouseOver).bind('mouseout', mouseOut);


  // then to unbind
  $('.myLink').click(function(e) {
    e.preventDefault();
    $('.myLink').unbind('mouseover', mouseOver).unbind('mouseout', mouseOut);
  });

});

Answer 8

I found this works as second argument (function) to .hover()

$('#yourId').hover(
    function(){
        // Your code goes here
    },
    function(){
        $(this).unbind()
    }
});

The first function (argument to .hover()) is mouseover and will execute your code. The second argument is mouseout which will unbind the hover event from #yourId. Your code will be executed only once.