I'm making a simple calculator program for a class project. I have an Exception handler that catches errors and returns the error type. Though whenever it catches an Exception, it prints the error type along with its description. Is there a way to only have it print the error type?
Code:
operations = ('Add', 'Subtract', 'Multiply', 'Divide')
def insigStrip(flt):
if str(flt)[-1] == '0':
return int(flt)
return flt
def main():
print('Select operation:')
for i in range(len(operations)):
print(str(i+1) + ':', operations[i])
while True:
try:
option = int(input('Enter choice(1/2/3/4): '))
if option in range(len(operations) + 1):
x = insigStrip(float(input('Enter first number: ')))
n = insigStrip(float(input('Enter second number: ')))
if option == 1:
print(x, '+', n, '=', insigStrip(x+n))
if option == 2:
print(x, '-', n, '=', insigStrip(x-n))
if option == 3:
print(x, '*', n, '=', insigStrip(x*n))
if option == 4:
try:
print(x, '/', n, '=', insigStrip(x/n))
except ZeroDivisionError:
print('Cannot divide by Zero.')
break
else:
print('Invalid input.')
continue
except Exception as e:
print('Error caught:', repr(e))
if __name__ == '__main__':
main()
For x or n, it only accepts 1, 2, 3, or 4 as input. Say for example, I were to input t for x. This would raise a ValueError. The try except statement inside the while loop then catches said ValueError and prints out Error caught: type(error).
Desired Output:
>>> t
Error caught: ValueError
Given output:
>>> t
Error caught: <class 'ValueError'> (if type(e))
or:
>>> t
Error caught: ValueError: insert error description (if repr(e))
How do I get the desired output?
