Recently I wrote a command-line parsing script using argparse in Python:
# tmp.py
import argparse
args = argparse.ArgumentParser()
args.add_argument('-warmup_proportion', type=float, default=0.1,
help="Proportion of training to perform linear learning rate warmup for E.g., 0.1 = 10% of training.")
args.parse_args()
When I run above code:
$python tmp.py -h
It raised a TypeError(only the last few rows for short):
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 284, in format_help
help = self._root_section.format_help()
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 215, in format_help
item_help = join([func(*args) for func, args in self.items])
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 215, in <listcomp>
item_help = join([func(*args) for func, args in self.items])
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 215, in format_help
item_help = join([func(*args) for func, args in self.items])
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 215, in <listcomp>
item_help = join([func(*args) for func, args in self.items])
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 531, in _format_action
help_text = self._expand_help(action)
File "/Users/sunjiawei/opt/anaconda3/envs/py-37-ner/lib/python3.7/argparse.py", line 620, in _expand_help
return self._get_help_string(action) % params
TypeError: %o format: an integer is required, not dict
If I delete 0.1 = 10% in help strings, it just worked OK. Is it a bug or something?
My Python is 3.7.9 for MacOS.
