Is there a way to get a list of all pep8 violations using pycodestyle?

Question

I want to check a file using pycodestyle. I've tried using what their docs say:

import pycodestyle

fchecker = pycodestyle.Checker('testsuite/E27.py')
file_errors = fchecker.check_all()
# I took off the show_source=True and the final print

It prints the errors, but file_errors is the NUMBER of errors, not the errors themselves. I want the errors to be returned in a list. How can I do that using pycodestyle?

More details

pycodestyle is a module that checks code against the PEP8 guidelines. Usually, it is used with the command line, but I want to automate it by putting it into a script. Using the docs, you get:

import pycodestyle

fchecker = pycodestyle.Checker('testsuite/E27.py', show_source=True)
file_errors = fchecker.check_all()

print("Found %s errors (and warnings)" % file_errors)

This prints the errors and the total amount of errors. However, file_errors is not a list- it's the number of errors.

I would want a way to get a list from pycodestyle.Checker (or any thing in pycodestyle). How can I do that?

What I've done: I've looked on google, and skimmed pycodestyle's docs, but nothing is mentioned.

Answer 1

From skimming the source code, it doesn't seem to have any way to return the errors, just print them. So you can capture its stdout instead.

from contextlib import redirect_stdout
import io

f = io.StringIO()  # Dummy file
with redirect_stdout(f):
    file_errors = fchecker.check_all()
out = f.getvalue().splitlines()  # Get list of lines from the dummy file

print(file_errors, out)

^{This code is based on ForeverWintr's answer}

For example, run it on a file like this:

s  = 0

Output:

1 ['tmp.py:1:2: E221 multiple spaces before operator']