How to use far arrow syntax when creating a Prototype?

Asked Oct 09 '20 at 23:06

Active Oct 09 '20 at 23:31

Viewed 24 times

If I want to a create prototype on String, how can I do so with the ES6 fat arrow syntax and return the string. If I do :

String.prototype.foo = () => {
   return this
}

..it returns the Window object, which makes sense since this is binded with the fat arrow.
How exactly would I return this?

asked Oct 09 '20 at 23:06

ddjk

1

You can't. Don't use arrow functions if you need to capture the calling context. – CertainPerformance Oct 09 '20 at 23:07
thank you, makes sense – ddjk Oct 09 '20 at 23:08
Also don't pollute global namespaces. String already has a prototype, and things work best if you leave all built-ins alone. – Mike 'Pomax' Kamermans Oct 09 '20 at 23:37

0 Answers0