How to use regex pattern to match longer string?

Question

I have a text string, similar to below example,

I have 5-6 year of experience with 2-3 years experience in Java

I have used this below regex syntax to match it,

import re

pattern = '\d{1}-\d{1} year'
[(m.start(0), m.end(0),'Experience') for m in re.finditer(pattern, string)]

# results
5-6 year
2-3 year (In this case it's missing out the 's'.)

How to modify this pattern to also match 'years and year' which every is longest?

@DYZ I also need to extract if it's more than 9 years as well. — user_12, Jul 23 '20 at 06:10

DYZ · Accepted Answer · 2020-07-24T20:48:33.907

2

Add an optional "s": '\d{1,2}-\d{1,2}\s*years?'. I also changed '\d{1}' to '\d{1,2}' which means "one or two digits" (it's hard to imagine someone has more than 99 years of experience), and replaced one space with '\s*' - any number of spaces, including no spaces.

edited Jul 24 '20 at 20:48

answered Jul 23 '20 at 06:09

DYZ

45,526
9
47
76

what does `?` do in this pattern? – user_12 Jul 23 '20 at 06:09
Just as I said: it means "optional." – DYZ Jul 23 '20 at 06:10
1

@user_12, it makes trailing `s` optional. – Olvin Roght Jul 23 '20 at 06:10
1

I made some extra changes to handle two-digit numbers. – DYZ Jul 23 '20 at 06:14
@DYZ Is there a way to also catch pattern like `2-3years and 2-3year` without space. – user_12 Jul 23 '20 at 06:14
1

See the latest update. – DYZ Jul 23 '20 at 06:15

How to use regex pattern to match longer string?

1 Answers1