Implementing a non-greedy group in regex

Asked Jul 03 '20 at 21:15

Active Jul 03 '20 at 21:15

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I'm trying to implement a non-greedy group in my function.

(?!(\.){2,})(\s|\S)*((?:INDEPENDENT\s*AUDITORS'\s*REPORT\s*)+?|(?:Management's\s*Report)+?|(?:PART\s*III)+?))

The problem right now is that if the text has, for example, Independent Auditors' Report and Part III at the end of the text, it'll match up to the very end of the text. However, I'd like it so that it stops at the first instance in the group.

The +? is my attempt at a non-greedy match. How do I solve this?

Thanks!

asked Jul 03 '20 at 21:15

PurplePros

Do you mean like this? `^(?!\.{2}).*?(?:INDEPENDENT\s*AUDITORS'\s*REPORT\s*|Management's\s*Report|PART\s*III)` https://regex101.com/r/HAbOPJ/1 – The fourth bird Jul 03 '20 at 21:24
So, use a non-greedy `*?` with `(\s|\S)*`. Actually, do not use `(\s|\S)*?` use `[\s\S]*?` or better `(?s:.*?)` – Wiktor Stribiżew Jul 03 '20 at 21:55

Implementing a non-greedy group in regex

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