Remove decimal precision not rounding

Question

I am quite confused with the soultions for removing decimal precision using python.

For instance, I have the following number:

9.1234567891235 --> float.

I want to only 9 digits of number after decimal point. Not rounding.

And the end result also should be float.

I have gone through some solutions. but to hit this directly.

Just guide me to function that I can use.

Thanks

If you do not want to round. How about converting it to string and strip the rest of the decimals. There is a nice library in Python for safely handing decimals https://docs.python.org/3/library/decimal.html#module-decimal — mad_, Jun 09 '20 at 16:11
I think this post may be useful: https://stackoverflow.com/questions/8595973/truncate-to-three-decimals-in-python — Asriel, Jun 09 '20 at 16:18

score 3 · Answer 1 · answered Jun 09 '20 at 16:15

3

Does this work for you:

num = 9.1234567891235
print(float("%.9f" % num))
# 9.123456789

answered Jun 09 '20 at 16:15

panadestein

A small additing here, the environment i am in is Jython. So I am getting an following error TypeError: float argument required, not java.math.BigDecimal Any idea on this – Arun Sunderraj Jun 09 '20 at 18:03
@ArunSunderraj it works for me in Jython 2.7. You can also [Try it online!](https://tio.run/##K6gsycjPM9LNAtP//@eV5irYKljqGRoZm5iamVtYAhmmXAVFmXklGmk5@YklGkqqepZpSgqqCkClmpr//wMA "Python 2 (Jython) – Try It Online") – panadestein Jun 09 '20 at 19:06

warped · Answer 2 · 2020-06-10T06:46:57.510

1

a= 9.1234567891235

def round_down(a, decimals):
    return round(a - 0.5 * 10**(-decimals), decimals)

round_down(a, decimals=9)
9.123456789

edited Jun 10 '20 at 06:46

answered Jun 09 '20 at 16:17

warped

2 Answers2