Given the following test string:
one two Three FouR fiVe SiX 7even eit nine TEN e1eVen tWelve 13
this regular expression
^([^ ]*)(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?(?: ([^ ]*))?$
and this substitution string
$19 $10
I am looking to get the contents of a column and add a number after it, as shown in this demo
My expected result is one9 one0
However, as you can see, in the case of $10 in the substitution string, it is taking the 0 as part of the column number
I tried escaping the 0, like this $19 $1\0, but that did not work
Any help would be appreciated
