How to convert string hhmm to time in python

Question

How could I convert the below column Time 1 from string to time eg: Time2

Time1

438

448

1815

1758

Time2

04:38

04:48

18:15

17:58

Does this answer your question? [Parsing time string in Python](https://stackoverflow.com/questions/10494312/parsing-time-string-in-python) — mkrieger1, May 28 '20 at 17:28
Rather https://stackoverflow.com/questions/2265357/parse-date-string-and-change-format — mkrieger1, May 28 '20 at 17:29

score 1 · Answer 1 · answered May 28 '20 at 17:26

1

Try the datetime library

>>> Time1 = ['438','448','1815','1758']
>>> Time2 = []
>>> import datetime
>>> for t in Time1:
...     Time2.append(datetime.datetime.strptime(t,'%H%M').strftime('%H:%M'))
>>> print (Time2)
['04:38', '04:48', '18:15', '17:58']

answered May 28 '20 at 17:26

Prateek Dewan

1,411
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Ann Zen · Answer 2 · 2020-05-28T18:28:54.883

0

You can use formatted strings:

Time1 = ['438','448','1815','1758']
Time2 = [f'{t[:-2]}:{t[-2:]}' for t in Time1]
print(Time2)

Output:

['4:38', '4:48', '18:15', '17:58']

edited May 28 '20 at 18:28

answered May 28 '20 at 17:27

Ann Zen

17,892
6
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score 0 · Answer 3 · answered May 28 '20 at 17:36

To start, some of your time1 cases are not in the hhmm format: there are only three digits in 438, but this can be incorporated nonetheless.

import datetime
def convert_string_to_time(str):
    if len(str) < 4:
        return datetime.time(hour=int(str[0]), minute=int(str[1:3]))
    else:
        return datetime.time(hour=int(str[0:2]), minute=int(str[2:4]))

This will return a datetime.time object for each time string. If you want to have the time in the format hh:mm:ss use str(convert_string_to_time(your string here))

How to convert string hhmm to time in python

3 Answers3