Getting KeyError: 'url' with PyTube

Question

I get the error sometimes when downloading a video. For example, I can attempt to download the video and it will download, the next time I run the script that video will not download and the error will be thrown.

def search_youtube(song,randomString,playlist_name):
 results = YoutubeSearch(song, max_results=1).to_dict()
 for v in results:
    url = 'https://www.youtube.com' + v['link']
    print(url)

    _filename = song
    format_input = 'mp4'
    format_output = 'mp3'

    print("Downloading...." + ' ' + song)
    time.sleep(5)
    YouTube(url).streams.first().download(filename=randomString,output_path=playlist_name)

Is this the entire script? Can you add the complete traceback? — Shiva, May 22 '20 at 17:36

score 11 · Accepted Answer · answered Jun 28 '20 at 14:21

I have just fixed this issue. Follow these steps.

Go to pytube directory in site-packages. If you're not sure where full location is use: pip show pytube3. You'll see location of site-packages.
In site-packages/pytube folder opened from above location, you'll see a file called extract.py. Open that file in your IDE or text-editor.
You'll see a function called apply_descrambler . Inside that function, in line 301 probably, you'll see something like parse_qs(formats[i]["cipher"]) for i, data in enumerate(formats)
Replace cipher in formats[i]["cipher"] with signatureCipher . Thus that line becomes, parse_qs(formats[i]["signatureCipher"]) for i, data in enumerate(formats)
pytube3 should work fine now.

Just worked for me (turned an error into a clean execute) -- thanks so much. — Jack Hales, Jul 18 '20 at 07:37

score 0 · Answer 2 · answered May 22 '20 at 17:57

I have something similar to your code, I hope it helps:

import webbrowser
import pytube
from subprocess import call

key = input('Input what you want to download: ')
a_website = "https://www.youtube.com/results?search_query="+key
webbrowser.open_new(a_website)

open('url.txt', 'w')
call(['notepad', 'url.txt'])

start = input('Press enter when ready to download >>> ')
with open('url.txt','r') as f:
    urls = f.readlines()
number = len(urls)
num = 0
for url in urls:
    num += 1
    print('Downloading video',num,'of',number)
    yt = pytube.YouTube(url)
    stream = yt.streams.first()
    stream.download()

open('url.txt', 'w')

score 0 · Answer 3 · answered May 22 '20 at 19:06

0

I decided to skip the videos that couldn't be downloaded due to the error message.

except KeyError as e:
       print ('I got a KeyError - reason "%s"' % str(e))
       print ('skipping the song - : ' + song)

answered May 22 '20 at 19:06

mruss24

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Getting KeyError: 'url' with PyTube

3 Answers3