Regular Expressions

Question

I am having trouble in using and decoding Strings Regular Expression.

Here is a pattern, "(?i)((^[aeiou])|(\\s+[aeiou]))\\w+[aeiou]\\b", and is to matched to "Arline ate eight apples and one orange while Anita hadn't any". Unable to identify the result, as to how.

the question is from Thinking in Java by Bruce Eckel, Strings Chapter.

Kindly enlighten.

Joel Hager · Answer 1 · 2020-05-16T06:50:03.803

-1

?i makes it case-insensitive. ((^[aeiou])|(\s+[aeiou])) means to start a capture group that starts with a vowel [aeiou] or a vowel that starts with any whitespace character \s. Then, one or more whitespace characters \w+, that finally ends with a vowel [aeiou]

edited May 16 '20 at 06:50

answered May 16 '20 at 06:16

Joel Hager

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?i means case-insensitive not sensitive.... – GolamMazid Sajib May 16 '20 at 06:31

GolamMazid Sajib · Accepted Answer · 2020-05-16T06:55:38.393

-2

Explaination:

(?i) -- means case-insensitive( its allow a-zA-Z)
^[aeiou] -- means start with aeiou
| - uses for or
\\s+[aeiou] -- means match one or more space then [aeiou]
\\w+ -- means match one or more word character(a-zA-Z0-9_)
\\b -- means end with word boundary

Demo here to test match.

Java Code:

String text = "Arline ate eight apples and one orange while Anita hadn't any";
        Pattern pattern = Pattern.compile("(?i)((^[aeiou])|(\\s+[aeiou]))\\w+[aeiou]\\b");
        Matcher matcher = pattern.matcher(text);
        while (matcher.find()) {
            System.out.println(matcher.group());
        }

Output:

Arline
 ate
 one
 orange
 Anita

edited May 16 '20 at 06:55

answered May 16 '20 at 06:24

GolamMazid Sajib

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not just space. *whitespace* character Tab, etc. – Joel Hager May 16 '20 at 06:49
You also forgot the or pipe `|` – Joel Hager May 16 '20 at 06:50

Regular Expressions

2 Answers2

Explaination:

Demo here to test match.

Java Code:

Output: