Bash - Print the full path of a file from $PATH

Question

Say I have ~/scripts in my $PATH and I have script.sh inside that path.

I can execute that script by typing script.sh directly in the terminal, but what if I want to print out the full path of that script without knowing the base path of the script (or added any function inside the script to print out its own path)? Are there any good ways to do this?

In any POSIX compliant shell, avoid `which`, there are builtins that are well suited for that, like `type` , `hash` and `command`, unless `which` is a builtin also from the shell you're using then sure use it. — Jetchisel, May 14 '20 at 01:23
@jared_mamrot Thank you, that did it! I don't know why it's borderline impossible to find the solution on google, I guess I wasn't using the right keywords — what the, May 14 '20 at 01:25
@Jetchisel Thank you, `command -v scriptname` seems to work well. — what the, May 14 '20 at 01:28
@Jetchisel can you tell me how to use `hash` to locate a file, do you refer to glibc ? — Max Muster, May 14 '20 at 01:38
@Jetchisel strange, I do not have it on my computer, `sh: 0: Can't open help` it is probably in bash ... — Max Muster, May 14 '20 at 02:11

score 1 · Accepted Answer · answered May 14 '20 at 01:26

1

In bash, to locate a file (script) in the users path, you can use the which command: (https://ss64.com/bash/which.html), but as @Jetchisel says there are better alternatives for POSIX-compliant shells; see 'which' vs 'command -v' in Bash

answered May 14 '20 at 01:26

jared_mamrot

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Bash - Print the full path of a file from $PATH

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