How would I approach calculating the quintiles from the csv file?
6
2
15
90
9
1
4
30
1
Output:
6,3
2,2
15,4
90,5
9,4
1,1
4,3
30,5
1,1
An awk version that doesn't care about the values but the place when sorted on the value. The quintilies are defined on the earlier revision of your question:
awk '
BEGIN {
FS=OFS=","
}
{
a[NR]=$0
}
END {
for(i=1;i<=int(0.2*NR);i++)
b[i]=1
for(;i<=(0.4*NR);i++)
b[i]=2
for(;i<=(0.6*NR);i++)
b[i]=3
for(;i<=(0.8*NR);i++)
b[i]=4
for(;i<=NR;i++)
b[i]=5
for(i=1;i<=NR;i++)
print a[i],b[i]
}' <(sort -t, -k3n file)
Output:
k,l,1,1
q,r,1,2 < this differs
c,d,2,2
m,n,4,3
a,b,6,3
i,j,9,4
e,f,15,4
o,p,30,5
g,h,90,5
Update: A more compact version that still relies on the position of the value in ordered list of values but keeps equal values in the same quintile.
$ awk '
BEGIN {
FS=OFS=","
}
{
a[NR]=$0 # hash all values index on order #
}
END { # after all values are hashed
for(i=1;i<=NR;i++) { # loop thru them all
j+=(i>j*0.2*NR&&a[i]!=p) # figuring out current quintile
print a[i],j # output
p=a[i]
}
}' <(sort -n file)
With GNU awk you could define PROCINFO["sorted_in"]="@val_num_asc"
and lose the sort
. Output for the latter version of OP's sample dataset:
1,1
1,1
2,2
4,3
6,3
9,4
15,4
30,5
90,5
Here's a shell script that uses sqlite3 to compute the quintiles with its ntile()
window function, which divides the values up into a given number of groups:
#!/bin/sh
printf "%s\n" \
"CREATE TABLE data(a, b, c INTEGER);" \
".import '$1' data" \
"SELECT a, b, c, ntile(5) OVER (ORDER BY c) FROM data ORDER BY rowid;" |
sqlite3 -csv -batch -noheader
Example:
$ ./quintile.sh input.csv
a,b,6,3
c,d,2,2
e,f,15,4
g,h,90,5
i,j,9,3
k,l,1,1
m,n,4,2
o,p,30,4
q,r,1,1
(This does require sqlite3
version 3.25 or newer)