Capture several consecutive expression with preg_match_all

Question

I need to capture several consecutive divs that I can recognize only with their start:

<div class="catched">
    something maybe with divs and more
</div>
<div class="catched">
    something else
</div>
<div class="catched">
    something else
</div>

However if I do preg_match('#<div class="catched">.+?<div class="catched"#i',$html,$match) it will only capture the first one. I already did that, I think it's with a non-capturing group but I don't find how to do and I don't remember how I did.

[Parsing HTML with regex is a hard job](https://stackoverflow.com/a/4234491/372239) HTML and regex are not good friends. Use a parser, it is simpler, faster and much more maintainable. See: http://php.net/manual/en/class.domdocument.php — Toto, Apr 28 '20 at 12:30
I know all that, but I also know there's a solution with regex... — Entretoize, Apr 28 '20 at 12:35

score 0 · Answer 1 · answered Apr 28 '20 at 12:52

You may use a HTML parser instead:

<?php
$junk = <<<EOT
<div class="catched">
    something maybe with divs and more
</div>
<div class="catched">
    something else
</div>
EOT;

$dom = new DOMDocument();
$dom->loadHTML($junk);

$xpath = new DOMXPath($dom);
$divs = $xpath->query("*/div[@class='catched']");
foreach ($divs as $div) {
    echo $div->nodeValue;
}

?>

Which yields

something maybe with divs and more

something else

For a quick, dirty and error-prone solution, you could use

preg_match_ll('~<div class="catched">(?s)(.+?)</div>~');

See a demo on regex101.com.

The regex will not work because there are nesteds `DIV`s, from OP: `something maybe with divs and more` — Toto, Apr 28 '20 at 13:29

Capture several consecutive expression with preg_match_all

1 Answers1