Accessing a list by index in a for loop

Question

I am trying to access specific elements in a list within a for loop. However, when a repeated item appears the index is given for the first instance.

For example:

my_list = [1,2,2,3,2,1]
for i in my_list:
     return my_list.index(i)

When the for loop has reached the last element it will return 0 rather than my desired output of 5. How do I get the index of the specific 'i' the loop is using?

Does this answer your question? [Accessing the index in 'for' loops?](https://stackoverflow.com/questions/522563/accessing-the-index-in-for-loops) — Andrew, Apr 17 '20 at 11:36

score 0 · Answer 1 · answered Apr 17 '20 at 11:37

0

Let say you want to find:

index_of = 2

Now lets get index of that element:

 [i for i in range(len([1,2,2,3,2,1])) if [1,2,2,3,2,1][i] ==index_of]

gives all index of that element:

[1, 2, 4]

answered Apr 17 '20 at 11:37

Joshua

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Why? There's `list.index()` which is better, faster and more compact. – Olvin Roght Apr 17 '20 at 11:41
list.index() returns the first index – Joshua Apr 17 '20 at 11:42
@OlvinRoght I didn't get you – Joshua Apr 17 '20 at 11:44

score 0 · Answer 2 · edited Apr 17 '20 at 11:52

0

Use enumerate():

for index, value in enumerate(my_list):
    print('Value {} at position {}'.format(value, index))

edited Apr 17 '20 at 11:52

Olvin Roght

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answered Apr 17 '20 at 11:40

Cblopez

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Accessing a list by index in a for loop

2 Answers2