Syntax error in bytes(" ".format(), encoding="utf-8")

Question

When running this:

import hashlib

hash1 = hashlib.md5(b'admin:Pentester Academy:asdds').hexdigest()
hash2 = hashlib.md5(b'GET:/lab/webapp/digest/1').hexdigest()
nonce = "526f295f84bcafc67598cd8e760a9cc5"

response_unhashed = (bytes("{}:{}:{}".format(hash1, nonce, hash2)), encoding='utf-8')
response_md5hashed = hashlib.md5(response_unhashed).hexdigest()

print(response_md5hashed)

I get this...

   Traceback (most recent call last):
  File "C:\Users\Adrian\Desktop\Infosec\Notes\Programming\example.py", line 7
    response_unhashed = (bytes("{}:{}:{}".format(hash1, nonce, hash2)), encoding='utf-8')
                                                         ^
SyntaxError: invalid syntax

Where's the syntax error? Checked some of the bytes() and format() documentation but couldn't find any clues.

You've added *too many* parentheses, so you have `(bytes( < ... >), encoding='utf-8')` you want `bytes(< ... >, encoding='utf-8')` — juanpa.arrivillaga, Apr 16 '20 at 03:20

score 0 · Accepted Answer · answered Apr 16 '20 at 03:30

0

There are parentheses that are in wrong order.

Try

bytes("{}:{}:{}".format(hash1,nonce,hash2), encoding = "utf-8")

Instead of

(bytes("{}:{}:{}".format(hash1, nonce, hash2)), encoding='utf-8')

answered Apr 16 '20 at 03:30

ax39T-Venom

22
5

score 0 · Answer 2 · answered Apr 16 '20 at 03:40

You can try this:

import hashlib
hash1 = hashlib.md5(b'admin:Pentester Academy:asdds').hexdigest()
hash2 = hashlib.md5(b'GET:/lab/webapp/digest/1').hexdigest()
nonce = "526f295f84bcafc67598cd8e760a9cc5"

response_unhashed = bytes("{}:{}:{}".format(hash1,nonce,hash2), encoding = "utf-8")
response_md5hashed = hashlib.md5(response_unhashed).hexdigest()

print(response_md5hashed)

Syntax error in bytes(" ".format(), encoding="utf-8")

2 Answers2