unix regex: match from end of string until white space character

Question

The git command:

git diff-tree --no-commit-id --name-status -r <commit hash>

generates a list that looks kinda like this:

D    path/to/deleted/file.txt
A    path/to/added/file.txt
A    path/to/added/file.asd
M    path/to/modified/file.txt

I want to grep out only the added and modified (A or M) txt files and their paths. I know I can do like this:

grep -v "^D"

to not include the deleted files.

and

grep -o "\w*.txt$"

to only get the txt files. But this command does not give me the path to the files. Since \w only matches the word. Is there any other wildcard that will match until the whitespace character (so that it removes the A/M with corresponding whitespace)?

So, you only want the .txt files? There is also an .asd file - should that NOT be shown in the output? — mathguy, Apr 06 '20 at 21:54

score 1 · Accepted Answer · answered Apr 06 '20 at 15:28

1

Use \S to match anything that isn't whitespace.

grep -o '\S*\.txt$'

answered Apr 06 '20 at 15:28

Barmar

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score 0 · Answer 2 · answered Apr 06 '20 at 15:38

0

awk /^A/^M/'{$0=$NF} 1'
path/to/added/file.txt
path/to/added/file.asd
path/to/modified/file.txt
$

answered Apr 06 '20 at 15:38

Digvijay S

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unix regex: match from end of string until white space character

2 Answers2