How to convert the time of a datetime object to an integer?

Question

I need the time between two points as integer, to calculate the speed of an object. My first thought was to do it with an datetime object, but I can’t convert it from string to int:

from datetime import datetime


#this is already the right format in HH:MM:SS:MS 

d = (datetime.now()).time().isoformat() 
coverted = int(d) # not working because of the ":"

i already found an solution here (see below), but the if i print the code, I just get a weird number which doesn't help me at all.

import time
from datetime import datetime
timestamp = int(time.mktime(datetime.now().timetuple())

Please provide a [mcve] including _code_ for what you've already tried based on your own research and a sample input and output — G. Anderson, Apr 02 '20 at 20:51
The "weird number that doesn't help you at all" is the number of seconds since 1.1.1970 — DeepSpace, Apr 02 '20 at 21:04
@DeepSpace I need the time between two points as integer, to calculate the speed of an object — Alfred Wächter, Apr 02 '20 at 21:10
@AlfredWächter `timestamp` already gives you time in seconds, so do `timestamp2 - timestamp1`. Don't invent a new way to deal with times because you *will* fail (timezones, leap-years, other fun time-related shenanigans). — DeepSpace, Apr 02 '20 at 21:15
@DeepSpace thanks for the explanation, but I need milliseconds as well. Timezones doesn’t matter in my case — Alfred Wächter, Apr 02 '20 at 21:17

score -1 · Accepted Answer · answered Apr 02 '20 at 21:08

First use your date format and cut the strings that you're looking for: (using Sub-String)

d = (datetime.now()).time().isoformat()   
min = d[3:-10]
seconds = d[6:-7]
milliseconds = d[9:]

Now you can use the int() command on your strings to convert them to Integers. For example:

min = int(min)
print min+1

Will print the current minute plus one.

How to convert the time of a datetime object to an integer?

1 Answers1