So I have a while-loop where you have 3 options to choose from and you choose them by inserting a number on standard input using a scanner, my code is like this:
int option;
String request;
Scanner input2 = new Scanner(System.in);
System.out.println("Choose an option:\n" + "1-Get camera information\n" + "2-Submit Data\n"
+ "3-Exit");
while(true){
try {
option = input2.nextInt();
if (option == 1) {
System.out.println("Camera name:");
request = input2.nextLine();
while (request.length() < 3 || request.length() > 15) {
System.out.println("Name has to be between 3 and 15 characters, insert a new one:");
request = input2.nextLine();
}
CamInfoRequest info_request = CamInfoRequest.newBuilder().setName(request).build();
if (stub.camInfo(info_request).getReturn() != 0) {
System.out.println("Camera does not exist");
} else {
System.out.println(stub.camInfo(info_request).getLatitude() + " " + stub.camInfo(info_request).getLongitude());
}
} else if (option == 2) {
System.out.println("submit");
} else if(option ==3){
break;
} else{
System.out.println("Invalid option.");
}
}catch(InputMismatchException e){
System.out.println("Invalid input");
}
}
So the way this is the code enters in an infinite loop when it catches the exception where it keeps printing "Invalid input", I tried using input2.next() at the catch but then he waits for another input I don't want, I can't use input2.close() either. What can I do?