Append string to words in snippets

Question

I am currently working on some Python snippets for VSCode using JavaScript regular expressions and I'd like to have one like :

Given

var1, var2, var3

Produce

self.var1 = var1
self.var2 = var2
self.var3 = var3

I currently know how to replace commas with line jump but not how to replace each word with another string. I'm pretty bad at regular expressions so it doesn't help. I think I'll need something that does the following :

var1, var2 -> self.var1 = var1, self.var2 = var2

Thanks for your help

Edit : From suggestions in comments I tried this : /(.*,)/self.$0 = $0/ It obviously doesn't work for several reasons : it matches all strings up to the last comma. VSCode doesn't give access to "\w" but i don't see how it would help. Other thing I tested that couldn't work either since I'm looking for duplicating each of the words : /(.*)/self.$0 = $0/

And since I didn't post it, here is the comme replacement by a new line : /[,]/\n/g

Edit2 (updated) : From comment suggestions I tried : /(.*?)(?:, |$)/self.$1 = $1\n/g which leads to almost perfect result :

toto, titi, tata

leads to

self.toto = toto
self.titi = titi
self.tata = tata
self. =

Please let us know what you tried to see where the issue is. — Wiktor Stribiżew, Mar 10 '20 at 14:50
I actually don't know how to try anything. As I said, I can replace commas with line jump (which is quite easy) but I don't know where to start. I'd like to select the beginning of each word and replace it with "self." as well as duplicating each word and appending an "=" before. But I don't know how to do it — Ricocotam, Mar 10 '20 at 14:52
Then [this](https://stackoverflow.com/questions/39837571/how-to-add-a-string-to-the-end-of-each-line-in-vs-code-using-regex) will give you a jumpstart. [Here](https://stackoverflow.com/questions/22937618/reference-what-does-this-regex-mean), you will find all the rest. — Wiktor Stribiżew, Mar 10 '20 at 14:55
Ok, so this doesn't help at all since I already went through the entire regex doc of JS and Python. I want ti duplicate a word and insert string before/after it. None of the thing I read answers this nor leads to an idea. — Ricocotam, Mar 10 '20 at 15:08
Why? Look, the first post tells you how to duplicate: once there is a match, `$0` is the backreference to the whole match. When you use it in the replacement pattern, you basically insert the match value. All you need is now a pattern to match what you need. If you need to match any word, use `\w+` (and that is clear once you open any basic regex tutorial, see http://regexone.com, e.g.) — Wiktor Stribiżew, Mar 10 '20 at 15:10
Ok so it was not clear at all since you linked something to add string at the end of a line. I tested what you explained but it does not work since I am matching any word, just as you said. But what I want is to duplicate each of the words : "toto, tata, titi" should give "toto toto, tata tata, titi titi" and it gives "toto, tata, titi toto, tata, titi" — Ricocotam, Mar 10 '20 at 15:16
Very good, please update the question with what you tried, what you got, and what you expected to get. — Wiktor Stribiżew, Mar 10 '20 at 15:21
I think we have something here, thanks @HarmvanderWal. Sadly it doesn't exactly work. I'll update the question — Ricocotam, Mar 10 '20 at 15:31
Sorry, I matched the wrong group. It should be: /(.*?)(?:, |$)/self.$1 = $1\n/ — Harm van der Wal, Mar 10 '20 at 15:33
Due to VSCode limitations, it seems I can't to use \1 ($1 is already used for another purpose) but your fix almost works — Ricocotam, Mar 10 '20 at 15:34
$0 is the full match on the regex. $1 is just the first captured group. How do you have $1 with another purpose? This is all I can do with the limited information you gave. — Harm van der Wal, Mar 10 '20 at 15:36
In VSCode snippets $1 is a place holder for the cursor (multicursor edition) and tab-stop functionnality. Thanks a lot, it honestly almost works, I'll try on VSCode forums/github to know is someone has an idea. You awesome @HarmvanderWal — Ricocotam, Mar 10 '20 at 15:38
All for the upvotes ;) Also: to not match on empty lines, try the following: /(.+?)(?:, |$)/self.$1 = $1\n/ — Harm van der Wal, Mar 10 '20 at 15:39
My bad, using $1 actually works. I'll update the post but I still have an issue. An extra line is added — Ricocotam, Mar 10 '20 at 15:43
If you want do have it done in 1 regex, this is the best I can do. If you use 2, it's a lot easier: 1: /, /\n/ 2: /^.+$/self.$0 = $0/ — Harm van der Wal, Mar 10 '20 at 15:48

rioV8 · Accepted Answer · 2020-03-10T23:49:13.560

3

Add the following to your python.json snippet file

  "var-init": {
    "prefix": "varinit",
    "body": [
      "${1/([\\w_]+)(?:[,\\s]|$)/self.$1 = $1\n/g}",
      "$0"
    ],
    "description": "var initialisation"
  }

Type the prefix: varinit
Press Tab
Type the variables you want separated by , with or without spaces: titi,tata,toto
Press Tab

Result

self.titi = titi
self.tata = tata
self.toto = toto

And the cursor on the next line.

Edit

A simplification of the regex and using the tip from Mark about the if-replacement ${2:+\n}

"${1/([\\w_]+)([, ])*/self.$1 = $1${2:+\n}/g}"

now the variables can be separated with spaces or ,

edited Mar 10 '20 at 23:49

answered Mar 10 '20 at 16:35

rioV8

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1

Looks familiar... I would suggest ` "${1/\\s*([^,]+)(,)*/self.$1 = $1${2:+\n}/g}",` as the regex is a little simpler and it doesn't add an extra newline after the last variable. And the spaces are handled much better. I get spaces added to the beginning of subsequent lines with your code. – Mark Mar 10 '20 at 16:59
1

It is also easy to modify this to where the variables are already listed and selected. If that is a use case for the OP. For more complicated cases of using variable numbers of arguments in a class constructor snippet see https://stackoverflow.com/questions/53998252/vscode-snippet-add-variable-number-of-objects-to-a-class-constructor/58459793#58459793 and for a class initializer see https://stackoverflow.com/questions/58225204/make-a-vscode-snippet-that-can-use-a-variable-number-of-arguments/58228253#58228253 – Mark Mar 10 '20 at 17:05

score 0 · Answer 2 · answered Mar 10 '20 at 16:01

You may use

Find What: \s*([^,\s]+)(?:,|$)
Replace With: self.$1 = $1\n

See the regex demo.

Details

\s* - 0 or more whitespaces
([^,\s]+) - capturing group 1: one or more chars other than whitespace and comma
(?:,|$) - a non-capturing group matching , or end of line.

Append string to words in snippets

2 Answers2