I am trying to write a code but facing a java.lang.StringIndexOutOfBoundsException. Please check the code out

Question

So I am trying to take multiple inputs. here is the question:- Given two strings of equal length, you have to tell whether they both strings are identical.

Two strings S1 and S2 are said to be identical, if any of the permutation of string S1 is equal to the string S2. See Sample explanation for more details.

Input : First line, contains an intger 'T' denoting no. of test cases. Each test consists of a single line, containing two space separated strings S1 and S2 of equal length.

Output:

For each test case, if any of the permutation of string S1 is equal to the string S2 print YES else print NO.

Constraints:

1<= T <=100

1<= |S1| = |S2| <= 10^5

String is made up of lower case letters only.


import java.io.*;
import java.util.*;
public class test
{
    public static void main(String args[])throws IOException
    {
        String parts[]=new String[10];
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter no of inputs");
        int n=sc.nextInt();
        int j=n;
        for(int i=0;i<j;i++)
        {
            System.out.println("Enter string");
            String s=sc.next();
            int in=s.indexOf(" ");
            String s1=s.substring(0,in);
            String s2=s.substring(in+1);
            boolean status = true;  
            if (s1.length() != s2.length()) 
            {  
                status = false;
            } 
            else 
            {  
                char[] ArrayS1 = s1.toCharArray();  
                char[] ArrayS2 = s2.toCharArray();  
                Arrays.sort(ArrayS1);  
                Arrays.sort(ArrayS2);  
                status = Arrays.equals(ArrayS1, ArrayS2);  
            }  
            if (status==true) 
            {  
                System.out.println(s1 + " and " + s2 + " are anagrams");  
            }    
            else 
            {  
                System.out.println(s1 + " and " + s2 + " are not anagrams");  
            }  
    }  
    }
}

java.lang.StringIndexOutOfBoundsException the error
where the issue persists issue

Which line is the error on? Please put a comment or mark it in some way. — NomadMaker, Feb 27 '20 at 19:55
`String s=sc.next();` - `s` will never contain a space, so `int in=s.indexOf(" ");` is `-1`. Try `sc.nextLine();` — Elliott Frisch, Feb 27 '20 at 19:56
When you try `nextLine()` be aware of this: [Scanner is skipping nextLine() after using next() or nextFoo()?](https://stackoverflow.com/q/13102045/5221149) — Andreas, Feb 27 '20 at 20:05

score 2 · Accepted Answer · answered Feb 27 '20 at 20:05

The issue is the statement

String s = sc.next();

That will never consume a token with a space (because white space is the delimiter). Change it to

String s = sc.nextLine();

And then

int in = s.indexOf(" ");

will work (but only if the input contains a space); so you should still test it is not -1 yourself.

if (in >= 0) {
    String s1 /* ... */
}

Also,

int n=sc.nextInt();

will leave trailing newlines (and skip your next input) using nextLine() so consume that too.

int n=sc.nextInt();
sc.nextLine(); // <-- skip trailing new line.

score 1 · Answer 2 · answered Feb 27 '20 at 20:14

Change your code as follows:

System.out.print("Enter no of inputs: ");
int n = Integer.parseInt(sc.nextLine());
for (int i = 0; i < n; i++) {
    System.out.print("Enter string: ");
    String s = sc.nextLine();
    ...
    ...
    ...
}

A sample run:

Enter no of inputs: 3
Enter string: Hello Hi
Hello and Hi are not anagrams
Enter string:

I recommend you go through Scanner is skipping nextLine() after using next() or nextFoo()? for a better understanding of Scanner.

score 0 · Answer 3 · answered Feb 27 '20 at 20:05

0

Try this:

System.out.println("Enter string");
sc.nextLine();
String s = sc.nextLine();

answered Feb 27 '20 at 20:05

Nibble

1
1

score 0 · Answer 4 · answered Feb 27 '20 at 20:07

Try below code. It print YES and NO according to your requirement.

import java.io.IOException;
import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;

// Main Class
public class ThreadGroupDemo implements Runnable {
    public void run() {
        System.out.println(Thread.currentThread().getName());
    }

    public static void main(String[] args) throws IOException {
        String parts[] = new String[10];
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter no of inputs");
        int n = Integer.parseInt(sc.nextLine());
        int j = n;

        for (int i = 0; i < j; i++) {
            System.out.println("Enter string");
            String s = sc.nextLine();
            int in = s.indexOf(" ");
            String s1 = s.substring(0, in);
            String s2 = s.substring(in + 1);
            boolean status = true;
            if (s1.length() != s2.length()) {
                status = false;
            } else {
                char[] ArrayS1 = s1.toCharArray();
                char[] ArrayS2 = s2.toCharArray();
                Arrays.sort(ArrayS1);
                Arrays.sort(ArrayS2);
                status = Arrays.equals(ArrayS1, ArrayS2);
            }
            if (status == true) {
                System.out.println("YES");
            } else {
                System.out.println("NO");
            }
        }
    }
}

I hope it helps.

I am trying to write a code but facing a java.lang.StringIndexOutOfBoundsException. Please check the code out

4 Answers4