Median timedelta in list

Question

With the help of this answer, I can calculate the average of a list of timedeltas in Python.

timedeltas = [ ... ]

# giving datetime.timedelta(0) as the start value makes sum work on tds 
average_timedelta = sum(timedeltas, datetime.timedelta(0)) / len(timedeltas)

Is there a solution for obtaining the median of timedeltas in a list?

You could sort the list, then pick the middle value, same way you calculate the median of any other sort of array — macaw_9227, Jan 08 '20 at 21:43

Kalma · Accepted Answer · 2020-01-08T21:50:54.490

1

Use statistics.median()

As an example:

import statistics

timedeltas = [1,2,3,4,5,6]
print(statistics.median(timedeltas))

importing statistics module, you can also use mean() (average value):

print(statistics.mean(timedeltas))

edited Jan 08 '20 at 21:50

answered Jan 08 '20 at 21:44

Kalma

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Thanks! The median works on timedelta, but for mean I get an error – Soroosh Sorkhani Jan 08 '20 at 22:02
Strange... Which error are you receiving? – Kalma Jan 08 '20 at 22:05
`TypeError: can't convert type 'timedelta' to numerator/denominator` – Soroosh Sorkhani Jan 08 '20 at 22:06
You're rigth! Never used it with timedeltas before. Use your code instead for the average value which is OK! – Kalma Jan 11 '20 at 20:47

Median timedelta in list

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