why i am getting Input MIsmatch Exception in this code?

Question

I am just trying to read integer, double , string values from keyboard. it just working fine for integer and double. but when it comes to string, it was throwing a Input Mismatch Exception, so i cant able to read string from keyboard.

import java.util.Scanner;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int i = scan.nextInt();
        double d= scan.nextInt();
        String s=scan.nextLine();

        // Write your code here.

        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + i);
    }
}

@user158302 can you tell me why you import the Scanner class separately?? — Akash, Jan 04 '20 at 14:23
"but when it comes to string, it was throwing a Input Mismatch Exception," is very had to believe since string can represent any characters provided by users so it shouldn't be mismatched. Other problem is that `nextLine()` most likely will return empty string (see [Scanner is skipping nextLine() after using next() or nextFoo()?](https://stackoverflow.com/q/13102045) for more details). — Pshemo, Jan 04 '20 at 14:57
Anyway to get proper answers we need to [edit] your question and provide proper [MCVE] (a.k.a. [SSCCE](http://sscce.org)) which aside from code also should include input you used while running your code and *exact* error message you are getting. — Pshemo, Jan 04 '20 at 14:58

score 1 · Answer 1 · edited Jan 04 '20 at 15:17

1

You have used double d= scan.nextInt();

instead use

double d= scan.nextDouble();

Moreover String is working fine for following input and output: 1 1 Hello

String: Hello

Double: 1.0

Int: 1

edited Jan 04 '20 at 15:17

Ashish Modi

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answered Jan 04 '20 at 14:31

Harsh Yadav

136
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I think it has nothing to do with the object type since the result of the input is promoted automagically to `double`. – snr Jan 04 '20 at 15:23
1 1.0 Hello Exception in thread "main" java.util.InputMismatchException – Harsh Yadav Jan 04 '20 at 16:14

score 0 · Answer 2 · answered Jan 04 '20 at 14:23

0

First, you're doing a scan.nextInt() for a double. Not the best thing to do. Second, try scan.next() to get an arbitrary type token.

        int i = scan.nextInt();
        double d= scan.nextDouble();
        String s=scan.next();

answered Jan 04 '20 at 14:23

WJS

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score 0 · Answer 3 · answered Jan 04 '20 at 15:16

please check the below code. it is working for me.

      public class Solution {

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);
        System.out.println("enter i value ");
        int i = scan.nextInt();
        System.out.println("enter d value ");
        double d= scan.nextDouble();
        System.out.println("enter s value ");
        String s=scan.next();


        // Write your code here.

        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + i);
    }

}

snr · Answer 4 · 2020-01-04T15:31:06.260

0

I think String s=scan.nextLine(); consumes the newline character coming from the followed calling double d= scan.nextInt();.

Here is my two cents.

double d = scan.nextInt();
scan.nextLine();
String s = scan.nextLine();

edited Jan 04 '20 at 15:31

answered Jan 04 '20 at 15:22

snr

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why i am getting Input MIsmatch Exception in this code?

4 Answers4