How to use regex to append characters before carriage return and newline

Asked Nov 22 '19 at 17:58

Active Nov 22 '19 at 17:58

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var = 'line1samplehere\r\nline2samplehere\r\nline3samplehere\r\n'
add = '12345'

I want to be able to search where '\r\n' is located and append the add string before that. I've researched and tried re.sub replacementre.sub(r'("\r\n"), add,var) but obviously having errors. Any advice?

asked Nov 22 '19 at 17:58

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What errors? Balance your quotes and use `add + '\r\n` – Mad Physicist Nov 22 '19 at 17:59
Don't put the double quotes around the part you're trying to capture, unless you want to capture those quotes. Change `r'("\r\n")` to `r'(\r\n)'`. – mypetlion Nov 22 '19 at 18:00
`var.replace('\r\n', add + '\r\n')`, no need for any regex. – Wiktor Stribiżew Nov 22 '19 at 18:25

How to use regex to append characters before carriage return and newline

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