why taking a character input in an integer variable returns 0 in c++?

Asked Nov 10 '19 at 19:48

Active Nov 10 '19 at 19:48

Viewed 49 times

Just from my curiosity in a c++ code i took character input in an integer variable then printed the value. The output of the variable is 0 .But i was expecting to see an ASCII value like 65 or something else. What is the reason behind this ? I used code::blocks to run this code .

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int x;
    cin>>x;
    cout<<x;
}

asked Nov 10 '19 at 19:48

Akram Hossain Rickon

1

Check the status of `std::cin` and you'll see that it reports failing to parse a decimal integer from your character, which makes sense. – Quentin Nov 10 '19 at 19:49
5

Please [don't include ``](https://stackoverflow.com/questions/31816095/why-should-i-not-include-bits-stdc-h). – Some programmer dude Nov 10 '19 at 19:51
1

As for your problem you tell the program to read `int` input. If the input isn't an `int` then you have an error. – Some programmer dude Nov 10 '19 at 19:52
Possible duplicate of [C++ character to int](https://stackoverflow.com/questions/2407771/c-character-to-int) – walnut Nov 10 '19 at 20:51

why taking a character input in an integer variable returns 0 in c++?

0 Answers0