User Input - Scanner Skips user inptu

Question

This is a simple test I made for my user input of my program but it skips over the second user input part. I am using sc.nextLine()

public static void main(String[] args)
{
    Scanner sc = new Scanner(System.in);
    int option;
    String name;

    System.out.println("1 or 2");
    option = sc.nextInt();

    if(option == 1)
    {
        System.out.println("Please enter a name");
        name = sc.nextLine();
        System.out.println(name);
    }
}

The program prints "1 or 2" The user selects 1 then the program prints the "please enter a name" theres a gap and the program ends?????? — NightPixel, Oct 22 '19 at 08:56
it's a classic issue. After your nextInt(); call, add another sc.next(); — Stultuske, Oct 22 '19 at 08:57
Similar to [this](https://stackoverflow.com/questions/13102045/scanner-is-skipping-nextline-after-using-next-or-nextfoo) — PftM, Oct 22 '19 at 08:58
I get what you are saying because thats to do with clearing the buffer? But if I put sc.next(); straight after the sc.nextInt(); it asks for user input again? — NightPixel, Oct 22 '19 at 09:01
@Stultuske `next()` __doesn't__ treat the enter/return. You're confusing it with `nextLine()` (or it was a typo in your first comment). — Tom, Oct 22 '19 at 09:27
@Tom you're right. Haven't used scanner for over a decade, I recognized the behavior, but ... :) — Stultuske, Oct 22 '19 at 09:36

score 0 · Answer 1 · answered Oct 22 '19 at 09:01

The problem is that the enter ("\n") from the first user input isn't a number and is used for the second. The quick and dirty option to fix this is to add a "sc.nextLine ();" after "nextInt()" line. Like:

    public static void main(String[] args)
{
    Scanner sc = new Scanner(System.in);
    int option;
    String name;

    System.out.println("1 or 2");
    option = sc.nextInt();
    sc.nextLine();

    if(option == 1)
    {
        System.out.println("Please enter a name");
        name = sc.nextLine();
        System.out.println(name);
    }
}

Oh ok sc.nextLine(); worked thanks – NightPixel Oct 22 '19 at 09:04 — NightPixel, Oct 22 '19 at 09:04

Jennis Vaishnav · Answer 2 · 2019-10-22T09:08:50.700

-1

Use sc.nextLine() after sc.nextInt() in your code.

edited Oct 22 '19 at 09:08

answered Oct 22 '19 at 09:00

Jennis Vaishnav

330
6
29

1

nope, that line is not the issue. It's expecting and end of line after the nextInt(); – Stultuske Oct 22 '19 at 09:01
updated that in the code. – Jennis Vaishnav Oct 22 '19 at 09:09

User Input - Scanner Skips user inptu

2 Answers2