Facing an issue while displaying output to the console

Question

I'm trying to store input in the array indoor_games and output it to the screen, but when I'm executing the code, it abruptly ends the execution after accepting 1 value.

package games;
import java.util.*;
import java.lang.*;
class Indoor{
  String name;
  Indoor(String name){
    this.name = name;
  }
  public void display(){
    System.out.println(this.name);
  }
}
class Outdoor{
  String name;
  Outdoor(String name){
    this.name = name;
  }
  public void display(){
    System.out.println(this.name);
  }
}
class Slip20{
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    String name;
    System.out.println("Enter number of Players in Indoor Games: ");
    int size = sc.nextInt();
    Indoor[] indoor_games = new Indoor[size];
      for(int i=0;i<size;i++){
        name = sc.next();
        indoor_games[i] = new Indoor(name);
      }
      for(int i=0;i<size;i++)
        indoor_games[i].display();
  }
}

Updated code with nextLine added but still the same problem:

class Slip20{
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    String name;
    System.out.println("Enter number of Players in Indoor Games: ");
    int size = sc.nextInt();
    sc.nextLine(); //To consume the newline character
    Indoor[] indoor_games = new Indoor[size];
      for(int i = 0 ; i < size ; i++){
        name = sc.nextLine();
        indoor_games[i] = new Indoor(name);   
      }
      for(int i = 0 ; i < size; i++)
        indoor_games[i].display();
  }
}

Output(Command Line)

D:\Docs Dump\School stuff\JAVA\Java slips>java games.Slip20

Enter number of Players in Indoor Games:

3

Neeraj

D:\Docs Dump\School stuff\JAVA\Java slips>

As you can see, the scanner only accepts "Neeraj" and the program ends

execution.

What are you expecting it to do, and based upon the code that you have, why are you expecting it to do it? — JonK, Oct 08 '19 at 12:06
You need to consume the end of line which you are not doing by solely calling `next()` and `nextInt()`. Fix it by calling `nextLine()`. — Murat Karagöz, Oct 08 '19 at 12:08
Tried that but still I'm not able to accept more than one value. — Supriya Honawale, Oct 08 '19 at 12:29
Just a general advice. You coding style looks much and much outdated. If you are learning Java now, make sure you get used to latest Java 8 standards. — madhairsilence, Oct 08 '19 at 12:31
You need to be more specific in your description of "it abruptly ends". How does it end? Does it throw you back into the command line? Does it display any error message? Just it just appear to hang by showing just blank space? — DodgyCodeException, Oct 08 '19 at 12:33
@DodgyCodeException Yes, my bad. I have made changed to the post. — Supriya Honawale, Oct 08 '19 at 12:41
Using your updated code I couldn't reproduce the issue. It ran fine. — DodgyCodeException, Oct 08 '19 at 14:07
I really don't know whats wrong then, I'm executing the same exact code. — Supriya Honawale, Oct 08 '19 at 15:33
Add some println statements all over the code to trace the flow of execution and find out exactly where it's failing. — DodgyCodeException, Oct 08 '19 at 15:38
I hadn't compiled the package and that was the problem, that's why whatever changes I was making weren't reflecting in the program. Thanks for the help though. — Supriya Honawale, Oct 08 '19 at 15:52

heyhooo · Answer 1 · 2019-10-08T12:15:50.770

0

just replace sc.next() by sc.nextLine()

edited Oct 08 '19 at 12:15

answered Oct 08 '19 at 12:07

heyhooo

82
6

And then you'll have [this problem](https://stackoverflow.com/q/13102045/3419894). Not to mention that `name` is a String. – JonK Oct 08 '19 at 12:12
Why the extra step Indoor indoor = new Indoor(name); indoor_games[i] = indoor? – Supriya Honawale Oct 08 '19 at 12:15
putting indoor in a variable let him to store the instance and usit to call the display method – heyhooo Oct 08 '19 at 12:16
But you can directly do that with indoor_games[i].display(), I feel its unnecessary.. – Supriya Honawale Oct 08 '19 at 12:40

score 0 · Answer 2 · answered Oct 08 '19 at 12:36

This is because nextLine() required. But be aware use it, documentation say that:

Advances this scanner past the current line and returns the input * that was skipped.

This method returns the rest of the current line, excluding any line * separator at the end. The position is set to the beginning of the next * line.

Known that you should use before loop and problem will be solved.

Scanner sc = new Scanner(System.in);
System.out.print("Enter number of Players in Indoor Games: ");
int size = sc.nextInt();
Indoor[] indoor_games = new Indoor[size];
sc.nextLine();
for (int i = 0; i < size; i++) {
    System.out.println("Please write a name:");
    indoor_games[i] = new Indoor(sc.nextLine());
}

score 0 · Answer 3 · answered Oct 08 '19 at 15:50

0

Hey thanks for the answers and help. It was actually a compilation problem, I was compiling the package in a wrong way. It's working now.

answered Oct 08 '19 at 15:50

Supriya Honawale

11
5

Facing an issue while displaying output to the console

3 Answers3