Regex to include empty matches with non-empty ones

Question

I need to regex every match of a string (including empty string!) separated by slash but the regex returns also empty string after each occurrence.

Examples (always 4 matches):

root/level1/level2/level3
/level1//level3
root/level1/level2/

Pattern:

I also tried to use IF-THEN-ELSE clause but it did not help :-(

I've searched dozens of articles but did not find any solution.

Use `[^\/]+` to match *1 or more* characters other than `/`. — Wiktor Stribiżew, Aug 27 '19 at 09:28
I does not solve my problem. This would work for only matches non empty strings but as I've written - I need both. — Michal, Aug 27 '19 at 10:47
You mean you need [`[^\/]+|(?<=\/)(?=\/)`](https://regex101.com/r/jBoDQ8/1)? — Wiktor Stribiżew, Aug 27 '19 at 10:49
Better but not perfect. Take a look at the link below. I need 5 matches but have only 3: https://regex101.com/r/pxRXEc/1 — Michal, Aug 27 '19 at 10:55
That's it! :) Thank you very much. How can I select your comments as the right answer? Sorry, this was my first question on stackoverflow... — Michal, Aug 27 '19 at 11:06

score 1 · Accepted Answer · answered Aug 27 '19 at 11:09

You may use

[^\/]+|(?<=\/|^)(?=\/|$)

See the regex demo and the regex graph:

Details

[^\/]+ - 1+ chars other than /
| - or
(?<=\/|^)(?=\/|$) - a location that is immediately preceded with / or start of string and immediately followed with / or end of string.

1 Answers1