Getting "FileNotFoundError" when opening files

Question

I've written a script to open, read, and then close a text file, but I keep getting an error message saying it can't find the file I specify.

I've massively reduced the code but I still get the same error message.

The code:

txt = open("textf.txt", "r")
print(txt.read())
txt.close()

The error message from running the code:

Traceback (most recent call last):
  File "C:\Users\miles\AppData\Local\Programs\Python\Python36-32\openfiles.py", line 1, in <module>
    txt = open("textf.txt", "r")
FileNotFoundError: [Errno 2] No such file or directory: 'textf.txt'

Try putting in the full path to your file. It's probably not in the directory the script is looking in. — khelwood, Aug 02 '19 at 20:28
Are your python script and this text file in the same directory? With this code they have to be. — DetectivePikachu, Aug 02 '19 at 20:40

score 0 · Answer 1 · answered Aug 02 '19 at 20:36

0

It depends where you run your code from.

You can use an absolute path (like c:/path/to/file/textf.txt)

Or you can use

import os
this_dir = os.path.dirname(os.path.abspath(__file__))
print(this_dir)

to check where your code is running, then move your file there.

Or you could add the path where the file is located to the PATH environment variable.

answered Aug 02 '19 at 20:36

Nimirium

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I don't think altering the PATH environment variable would solve the problem. PATH is where the shell will look for executable files. – khelwood Aug 02 '19 at 20:38

Getting "FileNotFoundError" when opening files

The code:

The error message from running the code:

1 Answers1