Regex: How to match string which is not containing one certain character and it combinations side by side

Question

I am trying to match everything except * or ** or infinity number of *

I have already writed such regex:

^(?!\*).+$|^.*[^\*]$|(?<=\*).+

I need to add or statement which would remove match: '****' Or write entire new one which:

Should not match when *

Should not match when **

Should not match when ***

ect.

Should match when A9()*

Should match when *A9()

Should match when A(*

Should match when A*()*

Should match when A9*)

Should match when A9()

ect.

This is worded in a confusing way, are you trying to match all strings that are not a single string of * characters? — Chris Sandvik, Jul 03 '19 at 15:20
I am trying to match everything except * or ** or infinity number of * — KamilSocha91, Jul 03 '19 at 15:23
Should it match all strings, which do not contain multiple asterix marks in a row? — nick, Jul 03 '19 at 15:24
@nick if there is any character beside asterix than it should mark — KamilSocha91, Jul 03 '19 at 15:27
@Wiktor Stribiżew You are master of regex ;) I dont know how to mark your command as working one .. — KamilSocha91, Jul 03 '19 at 15:30
I already answered this kind of question, see [this answer](https://stackoverflow.com/a/37988661/3832970). — Wiktor Stribiżew, Jul 03 '19 at 15:37

Vitalii · Accepted Answer · 2019-07-03T15:31:54.687

0

You can use length operator to determine minimum length of each symbol. For example:

(\w{1,}\*{1,}|\w+)

UPD

To include special characters use this modifications:

([^*\s]{1,}\*{1,}|[^*\s]+)

edited Jul 03 '19 at 15:31

answered Jul 03 '19 at 15:22

Vitalii

1 Answers1