How to fix "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException" in java programming

Question

error image i want to view the data that i already add but it shows exception. can refer to the image

public static void viewRecord()throws IOException{
    File f= new File("file.txt");          // specify the file name and path here
    Scanner sc = new Scanner(f);
    System.out.println("ID  |Species    |Weight |Length |"
                       +"Num of working flippers|Time   |Date   |Location   |");
    while(sc.hasNextLine())
    {
        String currentLine= sc.nextLine();
        String[] tokens = currentLine.split("#");
        System.out.println(tokens[0]+"\t"+tokens[1]+"\t\t"
                           +tokens[2]+"\t"+tokens[3]+"\t"+tokens[4]+"\t\t"+tokens[5]+"\t"
                           +tokens[6]+"\t"+tokens[7]);
    }
    sc.close();
}

when i already add the data it shows in the text file in one line not in line by line as i already add the data before

Your array index (the number between the brackets after tokens) is out of bounds (that is, less than zero or more than the last item in the tokens array). — rghome, Apr 30 '19 at 11:58
post the file contents in question. Your file have not a valid data according to your logic thats why exception occur. — Khalid Shah, Apr 30 '19 at 11:58

score -3 · Answer 1 · edited Apr 30 '19 at 12:01

-3

To avoid the ArryIndexOutOfBoundException you have to check the size of the tokens array before you expect it to have 8 elements:

while(sc.hasNextLine())
{
    String currentLine= sc.nextLine();
    String[] tokens = currentLine.split("#");
    if(tokens.length<8) {
        System.out.println("Invalid format in line:"+currentLine;
    } else {
        System.out.println(tokens[0]+"\t"+tokens[1]+"\t\t"+tokens[2]
          +"\t"+tokens[3]+"\t"+tokens[4]+"\t\t"+tokens[5]+"\t"
          +tokens[6]+"\t"+tokens[7]);
    }
}

edited Apr 30 '19 at 12:01

Reporter

3,547
5
28
45

answered Apr 30 '19 at 12:00

Conffusion

4,092
2
13
19

If you don't like this answer please tell me why so I can learn from it – Conffusion Apr 30 '19 at 12:12
1

I didn't down-vote it, but the question has already been asked many times before and is already answered in the duplicate question. In my opinion, it is better to close and move-on. – rghome Apr 30 '19 at 13:05
ok Thanks for your time @rghome – Conffusion Apr 30 '19 at 13:07

How to fix "Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException" in java programming

1 Answers1