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I want to capture Integer in between certain string. My Regular Expression String is re_str = "HOWMUCH？*\s*＿*\s*(\s*(\d+)\s*)＿*\s*USD"

target_text = " 1. HOWMUCH？＿＿10＿ USD
 1. HOWMUCH？＿20＿USD
 1. HOWMUCH？30＿＿ USD
 1. HOWMUCH？＿＿40＿＿＿ USD
 1. HOWMUCH？  50 USD
 1. HOWMUCH？ ＿＿60＿＿＿USD"
# I need to capture all int: 10, 20, 30 ... 60

Works well in here: regex101

I have tried re.findall

m = re.findall(r'{}'.format(re_str), target_text)
m:  [('20', '20')]

also tried re.search, got the same results. python repl

Environment: Python2.7

SOLVED
I modified RegExp to HOWMUCH？*[\s]*[＿]*[\s]*(\s*(\d+)\s*)[＿]*[\s]*USD then it works !

stackoverYC
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  • [`re.findall`](https://docs.python.org/2/library/re.html#re.findall): *If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group.* – Wiktor Stribiżew Apr 20 '19 at 08:16
  • I modified the question, it's a python regexp question, not the behavior on re.findall() function. – stackoverYC Apr 20 '19 at 08:34
  • Note that your [original regex](https://regex101.com/r/XpKeQt/1) also works the same, there is no issue. Just when you use 2 capturing groups you will have a list of tuples in the output. Why did you use two capturing groups? `？[＿\s]*(\d+)[＿_\s]*USD` also works, see [demo](https://regex101.com/r/MdtCv1/1), and there will be only numbers in the list. – Wiktor Stribiżew Apr 20 '19 at 09:10

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