JavaScript.Closures and transfered arguments

Question

We have a function:

function f (a, b, c) {
function sum (a, b) {
return a + b;
}
}

Rewrite it as follows:

If arguments a and b not transfered, they're equals by default 2 and 3.
If argument c transfered and is a function, then it will run after the function sum called.
Function f must return the result of a function argument c,if it exist,or result of a function sum.

Oops! I thought you were just posting a homework question without any work done because you put your comments in the quote. Try to preview your post to make sure it's properly formatted before posting next time! — Domino, Mar 04 '19 at 18:17
Formatting aside, it is extremely unclear what you're asking. — Domino, Mar 04 '19 at 18:19

Kamil Kiełczewski · Accepted Answer · 2019-03-04T18:40:07.763

0

If I good understand your question this should be ok:

function f (a = 2, b = 3, c) {
    function sum(a, b) {
        return a + b;
    }
    let s =  sum(a,b);
    return c instanceof Function ? c() : s;
}

console.log(f());
console.log(f(7,8));
console.log(f(9,10, ()=>11));

We use here ternary operator, instanceof operator, and arrow function

edited Mar 04 '19 at 18:40

answered Mar 04 '19 at 18:22

Kamil Kiełczewski

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Sorry for a question.But what arguments in these two logs ? Is it arrow function ? console.log(f(7,8)); console.log(f(9,10, x=>11)); – Artem Poznyak Mar 04 '19 at 18:37
`x=>11` is arrow function (which always return 11). Change it to `()=>3` and watch what happen. (I update answer and change it to ()=>11 because in function `f` in return... c() we not put any argument to x. – Kamil Kiełczewski Mar 04 '19 at 18:37
Oh,i think i got it.Thank you a lot ;) – Artem Poznyak Mar 04 '19 at 18:43

JavaScript.Closures and transfered arguments

1 Answers1