Extracting Data from OrderedDict

Question

So i have a firebase database

and this is my code to get specific data

db = firebase.database()
test = db.child("Users").order_by_child("IDNumber").equal_to(222333123).get().val()

print(test)

then the result returns as an OrderedDict

OrderedDict([('Ays', {'Ays': 'Baby', 'IDNumber': 222333123})])

i want to extract the data and have Ays = Baby and IDNumber = 222333123 as two separate variables. i tried using .items() and putting it into list but i can't seem to separate it. is there any other way?

`print(test["Ays"]["IDNumber"])` & `print(test["Ays"]["Ays"])` ? — Rakesh, Feb 05 '19 at 06:56
let's say OrderedDict([('SomeNameThatIDontKnow', {'Ays': 'Baby', 'IDNumber': 222333123})]) — Ezz Redfox, Feb 05 '19 at 07:16

score 4 · Accepted Answer · answered Feb 05 '19 at 07:01

4

There can be several items in the OrderedDict. It is always safe to iterate the list

from collections import OrderedDict
od = OrderedDict([('Ays', {'Ays': 'Baby', 'IDNumber': 222333123}), ('Ays1', {
    'Ays1': 'Baby1', 'IDNumber1': 222333123})])

for val in od.values():
    for k, v in val.items():
        print(k, v)

Output:

Ays Baby
IDNumber 222333123
Ays1 Baby1
IDNumber1 222333123

answered Feb 05 '19 at 07:01

Jeril

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got it by adding v which contains the values i need into an array, thanks! – Ezz Redfox Feb 05 '19 at 07:40

score 1 · Answer 2 · answered Feb 05 '19 at 06:58

1

You can use .values() to extract key, value

>>> d = OrderedDict([('Ays', {'Ays': 'Baby', 'IDNumber': 222333123})])
>>> list(d.values())
[{'Ays': 'Baby', 'IDNumber': 222333123}]

answered Feb 05 '19 at 06:58

shafik

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i did try that one, but how can i extract Baby and 222333123 from the list? sorry but i'm just new to python – Ezz Redfox Feb 05 '19 at 07:18
You can iterate over the list to get the value – shafik Feb 05 '19 at 07:22

Extracting Data from OrderedDict

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