Unwanted slash on creating regex

Question

By this method I want to use a variable in regex but it creates an extra / in the output:

var counter = 0,
    replace = "/\$" + counter;
    regex = new RegExp(replace);
    console.log(regex);

The output is /\/$0/ while I expected /\$0/, would you tell me what's wrong with it?

So, why add `/` to the `replace` variable in the first place? You seem to want `replace = "\\$" + counter;` — Wiktor Stribiżew, Jan 22 '19 at 12:17

score 0 · Answer 1 · answered Jan 22 '19 at 12:21

The / at the front is being escaped because / characters must be escaped in regular expressions delimited by / (which is how the console expresses your regex when you log it).

The \ before the $ is lost because \ is an escape character in JavaScript strings as well as in regular expressions. Log replace to see that the \$ is parsed as $. You need to escape the \ itself if you want it to survive into the regular expression.

Jack Bashford · Accepted Answer · 2019-01-23T07:23:13.307

0

You're adding a / to your regular expression string before it's generated (generation adds /), and you need to escape the backslash:

var counter = 0;
var replace = "\\$" + counter;
var regex = new RegExp(replace);
console.log(regex);

edited Jan 23 '19 at 07:23

answered Jan 22 '19 at 12:23

Jack Bashford

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Unwanted slash on creating regex

2 Answers2