How to create a slug route excluding some slug in laravel routing?

Question

I've following routes currently.

$router->get('/contact-us','HomeController@contactUs')->name('contact-us');
$router->get('/about','HomeController@about')->name('about');

Now, I want to make general pages accessible form following route,

$router->get('/{slug}','SomeController@about')->name('general-page');

But main problem is contact us and about page matched with slug route and wrong controller is called. Is there any way to exclude such slugs from general page route.

Try to change their order. Something like that worked for me while a go — ljubadr, Jan 17 '19 at 08:21
Just add a prefix to one of them. you cant have two routes but with the same path. — GabMic, Jan 17 '19 at 08:25
@ijubadr So slug route should be after contact us and about routes ? — Sagar Gautam, Jan 17 '19 at 08:30
I remember using catch all route, and I placed it at the bottom — ljubadr, Jan 17 '19 at 08:33
It should be your last route definition. I have a similar setup. — Mozammil, Jan 17 '19 at 08:35
placing slug route at the end works for me. Thanks for your time guys. — Sagar Gautam, Jan 17 '19 at 08:38

piscator · Accepted Answer · 2019-01-17T09:00:48.087

4

You could add a pattern to your route, where the terms contact-us and about are excluded, like this:

$router->get('/{slug}','SomeController@about')
    ->where('slug', '^((?!about|contact-us).)*$')
    ->name('general-page');

For an explanation of the regex, see here

In this way the order of the route definitions has no consequence.

edited Jan 17 '19 at 09:00

answered Jan 17 '19 at 08:46

piscator

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How to create a slug route excluding some slug in laravel routing?

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