How to timeout a fuction in python

Question

I am calling a function named as func for each sentence in my corpus as follows in python.

count =0    
for sentence in sentences:
   count += 1
   results.append(func(sentence))

I want to pass the sentences that takes too long to process by using timeout (e.g., timeout after 30 seconds and print the sentence number).

I tried to use the solution mentioned in: Timeout on a function call and timeout-decorator library as well.

However, both of the solutions returned me the same error mentioned below.

signal.signal(signal.SIGALRM, handler)

AttributeError: module 'signal' has no attribute 'SIGALRM'

Is there a way to perform timeout in python 3? Please let me know if further details are needed.

Possible duplicate of [Postpone code for later execution in python (like setTimeout in javascript)](https://stackoverflow.com/questions/10154568/postpone-code-for-later-execution-in-python-like-settimeout-in-javascript) — Derte Trdelnik, Jan 11 '19 at 13:19

score 1 · Accepted Answer · answered Jan 11 '19 at 13:30

1

The signal package is part of UNIX/Linux package and needs to be installed. If you are on windows check this out https://github.com/Unity-Technologies/ml-agents/issues/7

answered Jan 11 '19 at 13:30

pkrulz

If it answered your question, can you please click the tick mark on the left side and accept it as answer – pkrulz Jan 12 '19 at 03:05
1

If you are on windows this might help. https://stackoverflow.com/questions/8420422/python-windows-equivalent-of-sigalrm – pkrulz Jan 12 '19 at 03:08

1 Answers1